不管怎么掰都是n*m-1
#include<cstdio> using namespace std; int main() { freopen("bpmp.in","r",stdin); freopen("bpmp.out","w",stdout); int n,m; scanf("%d%d",&n,&m); int ans=(1ll*n*m-1)%998244353; printf("%d",ans); }
不管怎么掰都是n*m-1
#include<cstdio> using namespace std; int main() { freopen("bpmp.in","r",stdin); freopen("bpmp.out","w",stdout); int n,m; scanf("%d%d",&n,&m); int ans=(1ll*n*m-1)%998244353; printf("%d",ans); }
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