题目传送门

#include <bits/stdc++.h>

using namespace std;

const int N = 15;
const int M = 110; //mod N=0 N=100

int l, r, n;
int a[N];
int dp[N][M];

int dfs(int pos, int sum, bool limit) {
    if (pos == -1) return !(sum % n);
    if (!limit && ~dp[pos][sum]) return dp[pos][sum];
    int res = 0, up = limit ? a[pos] : 9;
    for (int i = 0; i <= up; i++)
        res += dfs(pos - 1, sum + i, limit && i == a[pos]);
    return limit ? res : dp[pos][sum] = res;
}

int calc(int x) {
    memset(dp, -1, sizeof dp);
    int pos = 0;
    while (x) a[pos++] = x % 10, x /= 10;
    return dfs(pos - 1, 0, true);
}

int main() {
    while (cin >> l >> r >> n)
        cout << calc(r) - calc(l - 1) << endl;
    return 0;
}

相关文章:

  • 2021-08-25
  • 2021-07-25
  • 2021-09-01
  • 2021-12-09
  • 2021-10-29
猜你喜欢
  • 2022-01-26
  • 2022-12-23
  • 2022-03-06
  • 2021-08-21
  • 2021-09-19
  • 2021-12-22
  • 2022-02-12
相关资源
相似解决方案