【发布时间】:2019-03-27 17:52:09
【问题描述】:
当试图为一组数据绘制指数曲线时:
import matplotlib
import matplotlib.pyplot as plt
from matplotlib import style
from matplotlib import pylab
import numpy as np
from scipy.optimize import curve_fit
x = np.array([30,40,50,60])
y = np.array([0.027679854,0.055639098,0.114814815,0.240740741])
def exponenial_func(x, a, b, c):
return a*np.exp(-b*x)+c
popt, pcov = curve_fit(exponenial_func, x, y, p0=(1, 1e-6, 1))
xx = np.linspace(10,60,1000)
yy = exponenial_func(xx, *popt)
plt.plot(x,y,'o', xx, yy)
pylab.title('Exponential Fit')
ax = plt.gca()
fig = plt.gcf()
plt.xlabel(r'Temperature, C')
plt.ylabel(r'1/Time, $s^-$$^1$')
plt.show()
以上代码的图表:
但是,当我添加数据点 20 (x) 和 0.015162344 (y) 时:
import matplotlib
import matplotlib.pyplot as plt
from matplotlib import style
from matplotlib import pylab
import numpy as np
from scipy.optimize import curve_fit
x = np.array([20,30,40,50,60])
y = np.array([0.015162344,0.027679854,0.055639098,0.114814815,0.240740741])
def exponenial_func(x, a, b, c):
return a*np.exp(-b*x)+c
popt, pcov = curve_fit(exponenial_func, x, y, p0=(1, 1e-6, 1))
xx = np.linspace(20,60,1000)
yy = exponenial_func(xx, *popt)
plt.plot(x,y,'o', xx, yy)
pylab.title('Exponential Fit')
ax = plt.gca()
fig = plt.gcf()
plt.xlabel(r'Temperature, C')
plt.ylabel(r'1/Time, $s^-$$^1$')
plt.show()
以上代码产生错误
'RuntimeError: 未找到最佳参数:调用次数 函数已达到 maxfev = 800。'
如果maxfev 设置为maxfev = 1300
popt, pcov = curve_fit(exponenial_func, x, y, p0=(1, 1e-6, 1),maxfev=1300)
图表已绘制,但未正确拟合曲线。上面代码更改的图表,maxfev = 1300:
我认为这是因为第 20 点和第 30 点彼此太近了?为了比较,excel 将数据绘制成这样:
如何正确绘制这条曲线?
【问题讨论】:
-
更改初始猜测的最后一个值
p0=(1,1e-6,0)适合我的数据 -
谢谢 DavidG,这对我也有效。
标签: python scipy curve-fitting