在 Python 和 matplotlib 中连接 3D 散点图中的两个点

Question

在下面的代码中，如何在 .show() 指令之前创建由两行代码创建的连接每对散点图的线（即将绿色圆圈连接到黄色箭头）？

import matplotlib.pyplot
from mpl_toolkits.mplot3d import Axes3D

dates       = [20020514, 20020515, 20020516, 20020517, 20020520]
highs       = [1135, 1158, 1152, 1158, 1163]
lows        = [1257, 1253, 1259, 1264, 1252]
upperLimits = [1125.0, 1125.0, 1093.75, 1125.0, 1125.0]
lowerLimits = [1250.0, 1250.0, 1156.25, 1250.0, 1250.0]

zaxisvalues0= [0, 0, 0, 0, 0]
zaxisvalues1= [1, 1, 1, 1, 1]
zaxisvalues2= [2, 2, 2, 2, 2]

fig = matplotlib.pyplot.figure()
ax  = fig.add_subplot(111, projection = '3d')

ax.plot(dates, zaxisvalues1, lowerLimits, color = 'b')
ax.plot(dates, zaxisvalues2, upperLimits, color = 'r')

ax.scatter(dates, zaxisvalues0, highs, color = 'g', marker = "o")
ax.scatter(dates, zaxisvalues0, lows, color = 'y', marker = "^")

matplotlib.pyplot.show()

Answer 1

在这些点之间画一条线段：

import matplotlib.pyplot
from mpl_toolkits.mplot3d import Axes3D

dates       = [20020514, 20020515, 20020516, 20020517, 20020520]
highs       = [1135, 1158, 1152, 1158, 1163]
lows        = [1257, 1253, 1259, 1264, 1252]
upperLimits = [1125.0, 1125.0, 1093.75, 1125.0, 1125.0]
lowerLimits = [1250.0, 1250.0, 1156.25, 1250.0, 1250.0]

zaxisvalues0= [0, 0, 0, 0, 0]
zaxisvalues1= [1, 1, 1, 1, 1]
zaxisvalues2= [2, 2, 2, 2, 2]

fig = matplotlib.pyplot.figure()
ax  = fig.add_subplot(111, projection = '3d')

ax.plot(dates, zaxisvalues1, lowerLimits, color = 'b')
ax.plot(dates, zaxisvalues2, upperLimits, color = 'r')

for i,j,k,h in zip(dates,zaxisvalues0,lows,highs):
    ax.plot([i,i],[j,j],[k,h],color = 'g')

ax.scatter(dates, zaxisvalues0, highs, color = 'g', marker = "o")
ax.scatter(dates, zaxisvalues0, lows, color = 'y', marker = "^")

matplotlib.pyplot.show()

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