从表中返回所有，但仅在不同字段大于 1 的情况下返回

Question

SQL 2008

基本上我有一个如下所示的数据集：

AcctID  AcctType  AcctSubType  Curr  TransType  Amount  Sequence 
1        CCY       SET          EUR   Opening    1000   B
1        CCY       SET          EUR   BUY        -100   T
1        CCY       SET          EUR   SEL        100    T
1        CCY       SET          EUR   Closing    1000   B
2        CCY       SET          EUR   Opening    2000   B
2        CCY       SET          EUR   SEL        100    T
2        CCY       SET          EUR   Closing    2100   B
3        CCY       INC          EUR   Opening    1000   B
3        CCY       INC          EUR   SEL        200    T
3        CCY       INC          EUR   BUY        -100   T
3        CCY       INC          EUR   Closing    1100   B
4        CCY       SET          GBP   Opening    2000   B
4        CCY       SET          GBP   SEL        100    T
4        CCY       SET          GBP   Closing    2100   B

我想要做的是从数据集中返回所有数据，其中每种货币有多个资本账户（所以基本上不止一个不同的 AcctID）。资本账户由 AcctType = 'CCY' 和 AcctSubType = 'SET' 标识。我也只想要余额，所以其中 Sequence = 'B'。

所以对于上述数据集，将返回以下内容：

AcctID  AcctType  AcctSubType  Curr  TransType  Amount  Sequence 
1        CCY       SET          EUR   Opening    1000   B
1        CCY       SET          EUR   Closing    1000   B
2        CCY       SET          EUR   Opening    2000   B
2        CCY       SET          EUR   Closing    2100   B

我是这样开始的，但对如何在大于 1 的货币中包含不同的 AcctID 计数感到困惑：

;;with test (AcctID, AcctType, AcctSubType, Curr, TransType, Amount, Sequence)
as 
( 
select 1, 'CCY', 'SET', 'EUR', 'Opening', 1000, 'B'
union all select 1, 'CCY', 'SET', 'EUR', 'BUY', -100, 'T'
union all select 1, 'CCY', 'SET', 'EUR', 'SEL', 100, 'T' 
union all select 1, 'CCY', 'SET', 'EUR', 'Closing', 1000, 'B' 
union all select 2, 'CCY', 'SET', 'EUR', 'Opening', 2000, 'B' 
union all select 2, 'CCY', 'SET', 'EUR', 'SEL', 100, 'T'
union all select 2, 'CCY', 'SET', 'EUR', 'Closing', 2100, 'B' 
union all select 3, 'CCY', 'INC', 'EUR', 'Opening', 1000, 'B'
union all select 3, 'CCY', 'INC', 'EUR', 'SEL', 200, 'T' 
union all select 3, 'CCY', 'INC', 'EUR', 'BUY', -100, 'T' 
union all select 3, 'CCY', 'INC', 'EUR', 'Closing', 1100, 'B'
union all select 4, 'CCY', 'SET', 'GBP', 'Opening', 2000, 'B' 
union all select 4, 'CCY', 'SET', 'GBP', 'SEL', 100, 'T' 
union all select 4, 'CCY', 'SET', 'GBP', 'Closing', 2100, 'B' 
)
select *
from test t
where t.AcctType = 'CCY'
and t.AcctSubType = 'SET'
and t.Sequence = 'B'
and t.Curr in (select w.Curr
from test w
where w.AcctType = 'CCY'
and w.AcctSubType = 'SET'
and w.Sequence = 'B'
group by w.Curr
having COUNT(distinct w.AcctID) > 1)

现在这适用于数据集，但我担心的是，如果有不止一种货币和不止一个资本账户，这是否可行？我创建的代码是否适用于我想要实现的目标。

非常感谢

Answer 1

试试这个。

UPD。是的，您更新的代码似乎可以正常工作，

;with test (AcctID, AcctType, AcctSubType, Curr, TransType, Amount, Sequence) 
as  
(  
    select 1, 'CCY', 'SET', 'EUR', 'Opening', 1000, 'B' 
    union all select 1, 'CCY', 'SET', 'EUR', 'BUY', -100, 'T' 
    union all select 1, 'CCY', 'SET', 'EUR', 'SEL', 100, 'T'  
    union all select 1, 'CCY', 'SET', 'EUR', 'Closing', 1000, 'B'  
    union all select 2, 'CCY', 'SET', 'EUR', 'Opening', 2000, 'B'  
    union all select 2, 'CCY', 'SET', 'EUR', 'SEL', 100, 'T' 
    union all select 2, 'CCY', 'SET', 'EUR', 'Closing', 2100, 'B'  
    union all select 3, 'CCY', 'INC', 'EUR', 'Opening', 1000, 'B' 
    union all select 3, 'CCY', 'INC', 'EUR', 'SEL', 200, 'T'  
    union all select 3, 'CCY', 'INC', 'EUR', 'BUY', -100, 'T'  
    union all select 3, 'CCY', 'INC', 'EUR', 'Closing', 1100, 'B' 
    union all select 4, 'CCY', 'SET', 'GBP', 'Opening', 2000, 'B'  
    union all select 4, 'CCY', 'SET', 'GBP', 'SEL', 100, 'T'  
    union all select 4, 'CCY', 'SET', 'GBP', 'Closing', 2100, 'B'  
) ,
cte_2 AS (
    select AcctType, AcctSubType, Curr

    from test t 
    where 
        t.AcctType = 'CCY' 
        and t.AcctSubType = 'SET' 

    GROUP BY AcctType, AcctSubType, Curr
    HAVING COUNT(DISTINCT AcctID) > 1
)
SELECT test.* 
FROM test
INNER JOIN cte_2
    ON test.AcctType = cte_2.AcctType AND test.AcctSubType = cte_2.AcctSubType AND test.Curr = cte_2.Curr
WHERE test.Sequence = 'B'