我如何在psychopy中模拟操纵杆输入

Question

我正在处理别人的代码。代码是用python编写的，它依赖于操纵杆。我想用键盘或鼠标模拟操纵杆，但我在网上没有找到任何相关帮助

这里有一些相关代码

from psychopy.hardware import joystick
from input_handler import JoystickServer
... 
# Make sure one joystick is connected.
joystick.backend = 'pygame'
nJoysticks = joystick.getNumJoysticks()
logging.log(level=logging.EXP, msg='{} joysticks detected'.format(nJoysticks))

if nJoysticks == 0:
    print('There is no joystick connected!')
    core.quit()
else:
    J0 = JoystickServer(0, settings['Joystick0_DeadZone'])
    if nJoysticks > 1:
        J1 = JoystickServer(1, settings['Joystick1_DeadZone'])
    else:
        print('You need two joysticks to play!')
        core.quit()

Answer 1

试试这个。我将它用于使用鼠标或罗技游戏控制器的任务。本质上，您为鼠标或游戏控制器设置了一个名为 checkButtonState() 的新函数，它将调用相应的函数。

def joyCheckButtonState(self):
    return self.getButton(self)

def mouseCheckButtonState(self):
    return self.getPressed(self)[0]

def setButtonPress(bttnType,win=None):

    if bttnType.lower() == 'joystick':

        # First check to make sure joystick is connected
        nJoysticks = joystick.getNumJoysticks()
        # Throw an error if there's no joystick detected
        joystick.backend = 'pygame'
        myBttn = joystick.Joystick(0)
        setattr(myBttn,'checkButtonState',joyCheckButtonState)
    elif bttnType.lower() == 'mouse':
        myBttn = event.Mouse(visible=False,newPos=False,win=win)
        setattr(myBttn, 'checkButtonState', mouseCheckButtonState)
    else:
        print('Error! Unknown button type')

    return myBttn

现在您可以致电myBttn.getPressed() 获取所使用的任一硬件。