将定义的元素分配给 2D 数组 C

Question

我有 3 个大整数组，我想将它们添加到数组的不同行中。这些整数定义如下：

#define APARTMENT1_USAGES {0.000, 0, 0, 0, 0, 0, 0, 0, 0, 0.189, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.074, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.111, 0, 0, 0.000, 0, 0, 0, 0, 0, 0.065, 0.167, 0, 0, 0, 0.048, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0}
    #define APARTMENT2_USAGES {0, 0, 0, 0, 0, 0, 0, 0.130, 0, 0, 0, 0, 0, 0.176, 0, 0.125, 0, 0.000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.161, 0.000, 0.039, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0.000, 0.109, 0, 0.032, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.152, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0, 0.135, 0, 0, 0, 0, 0, 0, 0, 0, 0.100, 0, 0, 0.063, 0, 0, 0, 0, 0.000, 0, 0.025, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0.000, 0, 0, 0, 0, 0, 0.378, 0, 0.147, 0.229}
    #define APARTMENT3_USAGES {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.048, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0.000, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0, 0, 0, 0, 0, 0.000, 0, 0, 0, 0.01, 0.01, 0.02, 0.03, 0.03, 0, 0, 0, 0, 0.088, 0, 0}

我已经缩短了这些只是为了展示这个想法，它们通常是 30x24 元素。 我想要做的是将这些中的每一个加载到二维数组的一行中，但是在没有解释的情况下出现语法错误。我试过如下：

double apartmentUsage[3][30*24];
apartmentUsage[1][30*24] = APARTMENT1_USAGES;
apartmentUsage[2][30*24] = APARTMENT2_USAGES;
apartmentUsage[3][30*24] = APARTMENT3_USAGES;

Answer 1

您面临的错误之一如下： 如果定义array[3]，则可以在array[0]、array[1] 和array[2] 中存储三个值。 在你的代码中。它定义为apartmentUsage[3][..]，但以1 开头。 应该是这样的-

int multiply=30*24;
apartmentUsage[0][multiply] = APARTMENT1_USAGES;
apartmentUsage[1][multiply] = APARTMENT2_USAGES;
apartmentUsage[2][multiply] = APARTMENT3_USAGES;

**BUT** 这也不能完全解决您的问题。尝试在初始化本身中执行它，如 cmets 中所指出的 - double apartmentUsage[3][multiply] = {APARTMENT1_USAGES, APARTMENT2_USAGES, APARTMENT3_USAGES};