什么sql可以用来计算范围内的值

Question

我有2张桌子，我想得到结果

name   min   max     count-of-occource-table2-value
chr1   10001 20000   4
chr1   30001 40000   1
chr2   110001 260000  2
...    ...    ...     ...

表 1：

name  min  max
(chr1,(10001,20000))
(chr1,(30001,40000))
(chr2,(110001,260000))
(chr2,(160001,360000))
(chr3,(260001,410000))
(chr3,(360001,460000))
(chr3,(410001,560000))
(chr4,(460001,610000))
(chr4,(560001,660000))
(chr4,(610001,710000))

表2：

name  value
(chr1,10001)
(chr1,10015)
(chr1,10026)
(chr1,10030)
(chr1,30038)
(chr2,110101)
(chr2,160001)
(chr3,360101)
(chr3,410101)
(chr4,610100)
(chr4,610001)

如果 table1.name= table2.name && table2.value in table1[min,man] 则计数加 1

怎么做

select table1.name, table1.min,table1.max, table1.name= table2.name and table2.value in table1[min,man]的出现次数

Answer 1

SELECT A.name, A.min, A.max, SUM(CASE WHEN A.name = B.name AND (B.value BETWEEN A.min AND A.max) THEN 1 ELSE 0 END) AS countofoccourcetable2value
FROM table1 A
INNER JOIN table2 B ON A.name = B.name
GROUP BY A.name, A.min, A.max