【发布时间】:2011-12-26 10:48:42
【问题描述】:
我使用 Operational Monad 方法编写了一个具有 Writer 功能的 monad。然后我注意到它不能懒惰地工作。
在下面的代码中,有一个rogueWriter 执行无限多个语句,每个语句都写入一个字符串。程序不会终止,只是需要无限输出的一些字符。
经过我的分析,我注意到流氓作家实际上非常友好(哈哈),因为当我从runMyWriter rogueWriter 更改为runWriter rogueWriter 时,一切顺利。
问题:
- 如何最好地解释这种行为?
- 我应该如何更改我的代码以使其正常工作?
- 什么 monad 转换器
SomeMonadT在SomeMonadT Writer w分别出现同样的问题。WriterT w SomeMonad(也许是一些例子?)
编辑:我是否有可能在这里尝试反转无限字符串? Sjoerd Visscher 的解决方案与我的一个显着区别是
w `mappend` ws resp. ws `mappend` w
代码:
{-# LANGUAGE GADTs, FlexibleContexts, TypeSynonymInstances,
FlexibleInstances, MultiParamTypeClasses #-}
module Writer where
import Control.Monad.Identity
import Control.Monad.Operational
import Control.Monad.Writer
import Data.Monoid
data MyWriterI w a where
Tell :: w -> MyWriterI w ()
type MyWriterT w = ProgramT (MyWriterI w)
type MyWriter w = (MyWriterT w) Identity
runMyWriterT :: (Monad m, Monoid w) => MyWriterT w m a -> m (a, w)
runMyWriterT prog = run prog mempty
where
run prog ws = viewT prog >>= flip eval ws
eval (Return a) ws = return (a, ws)
eval (Tell w :>>= is) ws = run (is ()) (ws `mappend` w)
runMyWriter :: (Monoid w) => MyWriter w a -> (a, w)
runMyWriter prog = runIdentity (runMyWriterT prog)
instance (Monad m, Monoid w) => MonadWriter w (MyWriterT w m) where
tell = singleton . Tell
listen = undefined
pass = undefined
-- Demonstration of the problem:
rogueWriter :: MonadWriter String m => m ()
rogueWriter = mapM_ (tell . show) [1..]
main = let (_, infiniteOutput) = runMyWriter rogueWriter
in putStrLn (take 20 infiniteOutput)
【问题讨论】:
-
IIRC,
operational上的 Monad.Reader 文章说你不能用它来做惰性状态单子;也许这是相关的。 -
看到
(tell . show)触发了小学的随机记忆:) -
@ehird 我不这么认为,因为 Sjoerd 的解决方案运行良好。
标签: haskell monads lazy-evaluation monad-transformers writer-monad