【发布时间】：2021-12-09 05:12:27
【问题描述】：
我写了一个用java解决钉子纸牌的程序。
我的程序得到一个起始板和一个目标板并尝试完成游戏。
我有一种计数器可以计算轮到我的次数，因为我有一个目的地有更多的 1 个挂钩，并且假设如果我只需要移除 2 个挂钩，那么我可以在 2 次移动中解决它。
我创建了一个板类：
public class Board {
private int board[][] = new int[7][7];
public Board(String place)
{
board[0][0]=2;
board[1][0]=2;
board[5][0]=2;
board[6][0]=2;
board[0][1]=2;
board[1][1]=2;
board[5][1]=2;
board[6][1]=2;
board[0][5]=2;
board[1][5]=2;
board[5][5]=2;
board[6][5]=2;
board[0][6]=2;
board[1][6]=2;
board[5][6]=2;
board[6][6]=2;
int loca=0;//location on the string of place
for(int i=0;i<7;i++){
for(int j=0;j<7;j++){
if(board[i][j]!=2) {
if (place.charAt(loca) == 'O') {
loca++;
board[i][j] = 1;
} else if (place.charAt(loca) == '.') {
loca++;
board[i][j] = 0;
}
}
System.out.print(board[i][j]);//print for test
}
System.out.println();//print for test
}
System.out.println();
}
public Board(Board copy){
for(int i=0;i<7;i++)
{
for(int j=0;j<7;j++)
{
board[i][j]=copy.getValue(i,j);
}
}
}
public int getValue(int x, int y)
{
return board[x][y];
}
public boolean isFinished(Board destination)
{
for(int i=0;i<7;i++)
{
for(int j=0;j<7;j++)
{
if(this.getValue(i,j)!=destination.getValue(i,j))
{
return false;
}
}
}
return true;
}
public Board turn(Board board,String direction,int x,int y)
{
if(direction.equals("right"))
{
board.setValue(x,y,0);
board.setValue(x+1,y,0);
board.setValue(x+2,y,1);
return board;
}
else if(direction.equals("left"))
{
board.setValue(x,y,0);
board.setValue(x-1,y,0);
board.setValue(x-2,y,1);
return board;
}
else if(direction.equals("up"))
{
board.setValue(x,y,0);
board.setValue(x,y-1,0);
board.setValue(x,y-2,1);
return board;
}
else if(direction.equals("down"))
{
board.setValue(x,y,0);
board.setValue(x,y+1,0);
board.setValue(x,y+2,1);
return board;
}
else{
System.out.println("there is not such direction, method turn on board class");
return null;//just for caution
}
}
public boolean isLegal(int x, int y){
if(board[x][y]==2)
{
return false;
}
else{
return true;
}
}
public boolean canTurn(String direction,int x,int y){
if(direction.equals("right"))
{
if(x<5) {
if (board[x][y] == 1 && board[x + 1][y] == 1 && board[x + 2][y] == 0) {
return true;
}
}
}
else if(direction.equals("left"))
{
if(x>1) {
if (board[x][y] == 1 && board[x - 1][y] == 1 && board[x - 2][y] == 0) {
return true;
}
}
}
else if(direction.equals("up"))
{
if(y>1) {
if (board[x][y] == 1 && board[x][y - 1] == 1 && board[x][y - 2] == 0) {
return true;
}
}
}
else if(direction.equals("down"))
{
if(y<5) {
if (board[x][y] == 1 && board[x][y + 1] == 1 && board[x][y + 2] == 0) {
return true;
}
}
}
else{
System.out.println("there is not such direction, method canTurn on board class");
return false;//just for caution
}
return false;
}
public void setValue(int x, int y, int value)
{
board[x][y]=value;
}
}
我写了我的“求解器”类。
public class PegSolver {
public int peg =1;
Board destinationBoard = new Board("OOOOOOOOOOOOOOOOO..OOOOOOOOOOOOOO");
Board board = new Board("OOOOOOOOOOOOOOOO.OOOOOOOOOOOOOOOO");
public void start(){
solve(0,board);
}
public boolean solve(int turn, Board board){
Board temp = new Board(board);
if(turn>peg)
{
return false;
}
else if(turn==peg){
//todo:check if solve
if(temp.isFinished(destinationBoard))
{
System.out.println("solution");
return true;
}
else
{
return false;
}
}
else//lower then 8
{
for(int i=0;i<7;i++){
for (int j=0;j<7;j++)
{
if(board.isLegal(i,j)) {
if(board.canTurn("right",i,j) && solve(turn++, temp.turn(temp, "right", i, j)))
{
return true;
}
else if(board.canTurn("left",i,j) && solve(turn++, temp.turn(temp, "left", i, j)))
{
return true;
}
else if(board.canTurn("up",i,j) && solve(turn++, temp.turn(temp, "up", i, j)))
{
return true;
}
else if(board.canTurn("down",i,j) && solve(turn++, temp.turn(temp, "down", i, j)))
{
return true;
}
}
}
}
}
return false;
}
}
当程序找到解决方案时，它需要打印“解决方案”，但由于某种原因，即使它是一个基本的目标，我的程序也无法找到解决方案。
有人可以帮帮我吗？
【问题讨论】：
-
见What is a debugger and how can it help me diagnose problems?。在您的代码中添加文档（cmets）也会有所帮助
-
代码中似乎存在索引和方向不一致：其中 x 表示水平索引，y 表示垂直索引数组索引应为
board[y][x]（而不是board[x][y]）
标签： java recursion depth-first-search