使用 Python 在 Seaborn 中设置散点图中点的大小答案

【问题标题】：Setting the size of points in scatterplot in Seaborn with Python使用 Python 在 Seaborn 中设置散点图中点的大小
【发布时间】：2019-05-28 09:44:29
【问题描述】：

我正在尝试根据代表其标签的列的值设置点的大小，但我得到一个空图。

此外，我想知道如何统一设置点的大小（即不管第三列的值如何）。

对于一个可重现的例子：

plot_data.to_json()
'{"x1":{"0":-0.2019455769,"1":0.1350610218,"2":-0.1128417956,"3":-0.1481016799,"4":0.1293273221,"5":-0.0266437776,"6":0.0100572041,"7":0.0037355635,"8":-0.0203400136,"9":0.1363267107},"x2":{"0":-0.1938001473,"1":-0.1353617432,"2":-0.0381057072,"3":-0.0874488661,"4":-0.2152329772,"5":0.0275324833,"6":-0.174604808,"7":-0.1872132566,"8":0.1172552524,"9":0.0166454137},"label":{"0":1,"1":0,"2":1,"3":0,"4":0,"5":1,"6":0,"7":0,"8":1,"9":0}}'

plt.figure(figsize = (20, 10))
sns.scatterplot(x ='x1', y='x2', hue = 'label', size = 'label', sizes = {0:1, 1:3} , data = plot_data)
plt.axis('equal')
plt.show()

【问题讨论】：

标签： python-3.x size seaborn scatter-plot

【解决方案1】：

您的代码非常接近：尺寸太小，无法轻松看到这些点。这里的代码使用sizes=(40, 40)，这使得最小和最大尺寸相同（参见docs）并给出统一的点尺寸：

import pandas as pd, seaborn as sns, matplotlib.pyplot as plt

plot_data = pd.read_json('{"x1":{"0":-0.2019455769,"1":0.1350610218,"2":-0.1128417956,"3":-0.1481016799,"4":0.1293273221,"5":-0.0266437776,"6":0.0100572041,"7":0.0037355635,"8":-0.0203400136,"9":0.1363267107},"x2":{"0":-0.1938001473,"1":-0.1353617432,"2":-0.0381057072,"3":-0.0874488661,"4":-0.2152329772,"5":0.0275324833,"6":-0.174604808,"7":-0.1872132566,"8":0.1172552524,"9":0.0166454137},"label":{"0":1,"1":0,"2":1,"3":0,"4":0,"5":1,"6":0,"7":0,"8":1,"9":0}}')

plt.figure(figsize = (10, 5))
sns.scatterplot(x='x1', y='x2', hue='label', size='label', sizes=(40, 40),
  data=plot_data)
plt.axis('equal')
plt.show()

结果如下：

【讨论】：