【发布时间】:2018-06-01 03:13:27
【问题描述】:
这是一个 xml 文件的一小部分。我想用这个创建一个数据库,每个标签都有唯一的列名和非重复数据。
尝试使用 lxml,到目前为止我能做的最好的事情是创建一个数据框,结果如下:
"
SRCSGT
DATE 11112017
AGENCY Department of Veterans Affairs
OFFICE Canandaigua VAMC
LOCATION Department of Veterans Affairs Medical Center
ZIP 14424
etc, etc, "
xml
<?xml version="1.0" encoding="UTF-8"?>
<NOTICES>
<SRCSGT>
<DATE>11112017</DATE>
<AGENCY><![CDATA[Department of Veterans Affairs]]></AGENCY>
<OFFICE><![CDATA[Canandaigua VAMC]]></OFFICE>
<LOCATION><![CDATA[Department of Veterans Affairs Medical Center]]></LOCATION>
<ZIP>14424</ZIP>
<CLASSCOD>H</CLASSCOD>
<NAICS>238210</NAICS>
<OFFADD><![CDATA[Department of Veterans Affairs;400 Fort Hill Ave.;Canandaigua NY 14424]]></OFFADD>
<SUBJECT><![CDATA[H--3 YEAR TESTING/MAINTENANCE OF ELECTRICAL EQUIPMENT AT THE SYRACUSE VA MEDICAL CENTER AND THE ROME COMMUNITY BASED OUTPATIENT CLINIC ]]></SUBJECT>
<SOLNBR><![CDATA[9069]]></SOLNBR>
<RESPDATE>11172017</RESPDATE>
<ARCHDATE>12172017</ARCHDATE>
<CONTACT><![CDATA[COiyiyS, JUhhiuN<a href="mailto:Juggyui@va.gov">CONTRACT SPECIALIST</a>]]></CONTACT>
<DESC><![CDATA[This is a Sources Sought Notice. (a) The Government does not intend to award a contract on the basis of this Sources Sought or to otherwise pay for the information solicited.(b) Although "proposal," "offeror," contractor, and "offeror" may be used in this sources sought notice, any response will be treated as information only. It shall not be used as a proposal.Attachment(s) if applicable. ]]></DESC>
<LINK><![CDATA[https://www.fbo.gov/spg/VA/CaVAMC532/CaVAMC532/9069/listing.html]]></LINK>
<EMAIL>
<ADDRESS><![CDATA[Jigjhgjas@va.gov]]></ADDRESS>
<DESC><![CDATA[CONTRACT SPECIALIST]]></DESC>
</EMAIL>
<SETASIDE>N/A</SETASIDE>
<RECOVERY_ACT>N</RECOVERY_ACT>
<DOCUMENT_PACKAGES>
<PACKAGE><![CDATA[Attachment]]></PACKAGE>
</DOCUMENT_PACKAGES>
</SRCSGT>
</NOTICES>
我写的代码
from lxml import etree as et
import pandas as pd
trees = et.parse('test.xml') #get xml file
root = trees.getroot() #get to root of file
tags = [] #list for holding all tags
datas = [] #list for holding all data in tags
for child in root: #root is a list of all elements in the xml file
#print(child.tag)
tt = child.tag #reads xml tag
tags.append(tt)
datas.append(child.text) #read xml tag data
for c in child.findall('./'): # ./ finds children
tt1 = c.tag
tags.append(str(tt1))
datas.append(c.text)
for i in c.findall('./'): #each child node loads a new list of elements
tt2 = i.tag
tags.append(str(tt1)+ '_' + str(tt2))
datas.append(i.text)
for j in i.findall('./'):
tt3 = j.tag
tags.append(str(tt1)+ '_' + str(tt2) + '_' + str(tt3))
datas.append(j.text)
for k in j.findall('./'):
tt4 = k.tag
tags.append(str(tt1)+ '_' + str(tt2) + '_' + str(tt3) + '_' + str(tt4))
datas.append(k.text)
df = pd.DataFrame({"tags": tags,"values": datas})
想要的解决方案是这样的
date agency office
1/1/10 A1 O1
1/1/10 A2 O2
1/1/10 A3 O3
所以基本上标签应该变成列标题并且必须被填充。列名不应重复,以便创建标准数据库表。
【问题讨论】:
-
到底是什么问题?你的 Python 代码在哪里?
-
抱歉 -- 添加了代码。但问题是要创建一个如上所述的数据框