OpenGL、SOIL 库和带纹理的矩形

Question

我正在尝试使用 SOIL 和 GLUT 在 OpenGL 中制作一个简单的纹理矩形。

这是我的显示函数（由 glutDisplayFunc(Display) 在 main 中执行）：

void Display ()
{
    GLuint tex_2d;

    glMatrixMode (GL_MODELVIEW);
    glLoadIdentity ();
    glClear (GL_COLOR_BUFFER_BIT);
    glClearColor (1.0,1.0,1.0,1.0);
    gluLookAt (eyex,eyey,eyez,centerx,centery,centerz,0,1,0);

    glEnable(GL_TEXTURE_2D);
     tex_2d = SOIL_load_OGL_texture
    (
        "img.png",
        SOIL_LOAD_AUTO,
        SOIL_CREATE_NEW_ID,
        SOIL_FLAG_MIPMAPS | SOIL_FLAG_INVERT_Y | SOIL_FLAG_NTSC_SAFE_RGB | SOIL_FLAG_COMPRESS_TO_DXT
    );
     if( 0 == tex_2d )
    {
        printf( "SOIL loading error: '%s'\n", SOIL_last_result() );
        exit(1);
    }

   glBindTexture(GL_TEXTURE_2D, tex_2d);

    glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_LINEAR_MIPMAP_LINEAR);
    glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_LINEAR_MIPMAP_LINEAR); 

    glColor3f (0.0,0.0,0.0);
    glBegin(GL_POLYGON);

                       glTexCoord2f(0.0f, 0.0f); glVertex2f(0.0f, 0.0f);
                       glTexCoord2f(1.0f, 0.0f); glVertex2f(1.0f, 0.0f);
                       glTexCoord2f(1.0f, 1.0f); glVertex2f(1.0f, 1.0f);
                       glTexCoord2f(0.0f, 1.0f); glVertex2f(0.0f, 1.0f);

     glEnd();   
    glDisable(GL_TEXTURE_2D);
    glFlush ();
    glutSwapBuffers();
}

这样只能看到一个没有任何纹理的黑色矩形。我试图用这个做几个小时。请帮忙，提前谢谢。

Answer 1

可能是您在绘制矩形之前将颜色设置为黑色吗？线

glColor3f (0.0,0.0,0.0);

试试白色吧……

glColor3f (1.0,1.0,1.0);