题目如下:

Given a valid (IPv4) IP address, return a defanged version of that IP address.

defanged IP address replaces every period "."with "[.]".

 

Example 1:

Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"

Example 2:

Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"

 

Constraints:

  • The given address is a valid IPv4 address.

解题思路:这个题目是来搞笑的吗?

代码如下:

class Solution(object):
    def defangIPaddr(self, address):
        """
        :type address: str
        :rtype: str
        """
        return address.replace('.','[.]')

 

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