zhangwenbiao

所谓“凑微分”是将

$$\alpha(x)f(x)+\beta(x)f\'(x)$$

表示成$[G(x)f(x)]\'$形式,其它项均与$f(x)$无关。例如:

$$f(x)+xf\'(x)=[xf(x)]\'$$

(1). 若$\beta\'(x)=\alpha(x)$,则

$$\alpha(x)f(x)+\beta(x)f\'(x)=[\beta(x)f(x)]\'$$

(2).若$\beta\'(x)\neq\alpha(x)$,设$\beta(x)\neq 0, x\in D$

$$\alpha(x)f(x)+\beta(x)f\'(x)=\beta(x)\left[f\'(x)+\frac{\alpha(x)}{\beta(x)}f(x)\right]$$

乘,除取值非零函数$g(x)$有

$$\frac{\beta(x)}{g(x)}\left[g(x)f\'(x)+g(x)\frac{\alpha(x)}{\beta(x)}f(x)\right]$$

令$$g\'(x)=g(x)\frac{\alpha(x)}{\beta(x)}$$

解得

$$g(x)=e^{\int \frac{\alpha(x)}{\beta(x)}dx}$$

我们称$g(x)$为积分因子.练习将以下个式写成全微分形式或求解常微分方程:

1. $$f(x)-xf\'(x)$$

2.$$f(x) \sin x +f\'(x)$$

3.$$f(x)-x^{-n}f\'(x)$$

4.$$f(x)+x^{n}f\'(x)$$

5.$$x^{n}f(x)+\frac{1}{1+x^{2}}f\'(x)$$

6.$$\alpha(x)f(x)+\beta(x)f\'(x)+h(x)=Q(x)$$

7.$$\alpha(x)f\'(x)+\beta(x)f\'\'(x)+h(x)=Q(x)$$

 

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