https://leetcode-cn.com/problems/maximum-subarray/
func maxSubArray(nums []int) int {
dp := make([]int,len(nums))
dp[0] = nums[0]
for i:=1;i<len(nums);i++{
dp[i] = MAX(dp[i-1],0)+nums[i]
}
res := nums[0]
for i:=1;i<len(nums);i++{
res = MAX(res,dp[i])
}
return res
}
func MAX(i,j int) int{
if i>j{
return i
}else{
return j
}
}
下面优化：使用常量空间复杂度O(1)
func maxSubArray(nums []int) int {
pre,res := nums[0],nums[0]
for i:=1;i<len(nums);i++{
cur := MAX(pre,0)+nums[i]
pre = cur
if cur > res{
res = cur
}
}
return res
}
func MAX(i,j int) int{
if i>j{
return i
}else{
return j
}
}