E. Prefix Free Code

大意: 给定$n$个串, 保证任意一个串都不是另一个串的前缀, 从中选出$k$个串可以拼成$\binom{n}{k}k!$种串. 给定其中一个串, 求这个串的排名.

先用字典树处理一下, 从而转化为给定一个$n$元素中取$k$元素的排列, 求排名.

#include <iostream>
#include <sstream>
#include <algorithm>
#include <cstdio>
#include <cmath>
#include <set>
#include <map>
#include <queue>
#include <string>
#include <cstring>
#include <bitset>
#include <functional>
#include <random>
#define REP(i,a,n) for(int i=a;i<=n;++i)
#define PER(i,a,n) for(int i=n;i>=a;--i)
#define hr putchar(10)
#define pb push_back
#define lc (o<<1)
#define rc (lc|1)
#define mid ((l+r)>>1)
#define ls lc,l,mid
#define rs rc,mid+1,r
#define x first
#define y second
#define io std::ios::sync_with_stdio(false)
#define endl '\n'
#define DB(a) ({REP(__i,1,n) cout<<a[__i]<<',';hr;})
using namespace std;
typedef long long ll;
const int P = 1e9+7;
const int N = 1e6+10;
ll inv(ll x){return x<=1?1:inv(P%x)*(P-P/x)%P;}
int n,k,ch[N][26],T,val[N],a[N],tot,cnt,len;
char s[N];
void add(int &o, char *s) {
    if (!o) o = ++tot;
    if (*s) add(ch[o][*s-'a'],s+1);
    else val[o] = 1;
}
void dfs(int o) {
    if (!o) return;
    if (val[o]) return val[o] = ++cnt,void();
    REP(i,0,25) dfs(ch[o][i]);
}
void find(int o, char *s) {
    if (val[o]) a[++*a]=val[o];
    else ++len,find(ch[o][*s-'a'],s+1);
}

int c[N];
void add(int x, int v) {
    for (; x<=n; x+=x&-x) c[x]+=v;
}
int qry(int x) {
    int ret = 0;
    for (; x; x^=x&-x) ret+=c[x];
    return ret;
}

int main() {
    scanf("%d%d",&n,&k);
    REP(i,1,n) scanf("%s",s),add(T,s);
    dfs(T);
    scanf("%s",s+1);
    int m = strlen(s+1);
    REP(i,1,m) len=0,find(T,s+i),i+=len-1;
    int tot = 1;
    REP(i,n-k+1,n) tot = (ll)tot*i%P;
    REP(i,1,n) c[i] = i&-i;
    int ans = 1;
    REP(i,1,k) {
        tot = (ll)tot*inv(n-i+1)%P;
        ans = (ans+(ll)qry(a[i]-1)*tot)%P;
        add(a[i],-1);
    }
    printf("%d\n",ans);
}
View Code

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