将xml反序列化为c#时获取xml属性的值答案

【问题标题】：Get value of xml attribute when desearlizing xml to c#将xml反序列化为c#时获取xml属性的值
【发布时间】：2020-04-30 06:14:27
【问题描述】：

我要做的是从下面 xml 的 Included_By_Organization 集合中的 ID 标记上的 type 属性中获取属性值。我可以很好地获取值，但属性返回 null。

包含在组织对象示例中：

Type: null

XML

<wd:Included_by_Organizations wd:Descriptor="RU7860 Europe Forwarding Overhead">
        <wd:ID wd:type="WID">b8129574800601751d8538accb023f35</wd:ID>
        <wd:ID wd:type="Organization_Reference_ID">RU7860</wd:ID>
        <wd:ID wd:type="Custom_Organization_Reference_ID">RU7860</wd:ID>
</wd:Included_by_Organizations>

xml 数组的类

        [XmlAttribute("type")]
        public string Type { get; set; }

        [XmlText]
        public string Value { get; set; }

        public IncludedByOrganization()
        {
        }

获取 xml 值的类

    [XmlElement("Reference_ID")]
    public string CostCenterId { get; set; }

    [XmlElement("code")]
    public string Code { get; set; }

    [XmlElement("name")]
    public string Name { get; set; }

    [XmlArray("Included_by_Organizations")]
    [XmlArrayItem("ID")]
    public IncludedByOrganization[] IncludedByOrganization { get; set; }

去沙化方法

        ReportData reportDataList = new ReportData();
        XmlSerializer serializer = new XmlSerializer(typeof(ReportData));

        using (var reader = XmlReader.Create(filePath))
        {
            ReportData reportData = (ReportData)serializer.Deserialize(reader);
            reportDataList = reportData;
        }

        return reportDataList;

【问题讨论】：

标签： c# xml

【解决方案1】：

根据您的示例，我创建了另一个示例并设法阅读了type。

[Serializable, XmlRoot()]
public class XML
{
    [XmlArray("Included_by_Organizations")]
    [XmlArrayItem("ID")]
    public IncludedByOrganization[] IncludedByOrganization { get; set; }
}

注意[Serialization, XmlRoot()] 的属性。

[Serializable]
public class IncludedByOrganization
{
    [XmlAttribute("type")]
    public string Type { get; set; }

    [XmlText]
    public string Value { get; set; }

    public IncludedByOrganization()
    {
    }
}

还添加了[Serialization]属性。

文字示例：

<?xml version="1.0" encoding="UTF-8"?>
<XML>
    <Included_by_Organizations Descriptor="RU7860 Europe Forwarding Overhead">
        <ID type="WID">b8129574800601751d8538accb023f35</ID>
        <ID type="Organization_Reference_ID">RU7860</ID>
        <ID type="Custom_Organization_Reference_ID">RU7860</ID>
    </Included_by_Organizations>
</XML>

示例存储在string xml。

XmlSerializer serializer = new XmlSerializer(typeof(XML));
var reader = new StringReader(xml);
var deserialized = serializer.Deserialize(reader);

结果：

【讨论】：