多个条件布尔逻辑 Python

Question

我能否获得有关 Python 中布尔条件逻辑的更好方法的提示？我正在尝试根据current_time 介于starttime 和endtime 之间以及其他布尔逻辑返回True 或False，以检查日期时间工作日编号的current_day 是周末还是工作日。

一个函数似乎最适合这个吗？任何提示都可以帮助我遇到一个问题，如果 Weekends 或 Weekdays 都是 False，这意味着该事件被禁用，或者如果 current_time 不在 starttime 和 endtime 之间，该事件也将被禁用，所以Return False

from datetime import datetime

now = datetime.now()
current_time = now.strftime("%H:%M")
print("Current Time is ", current_time)

# To Get the Week Number
current_day = datetime.today().weekday()
print("Current Weekday Number is ", current_day)   


data1 = {'setpoint': '366', 'Weekdays': 'True', 'Weekends': 'True', 'starttime': '02:40', 'endtime': '22:40'}
data2 = {'setpoint': '366', 'Weekdays': 'False', 'Weekends': 'True', 'starttime': '02:40', 'endtime': '22:40'}
data3 = {'setpoint': '366', 'Weekdays': 'True', 'Weekends': 'False', 'starttime': '02:40', 'endtime': '03:40'}
data4 = {'setpoint': '366', 'Weekdays': 'False', 'Weekends': 'False', 'starttime': '02:40', 'endtime': '22:40'}



def condition_checker(data,current_time,current_day):
    between_time = data['starttime'] <= current_time <= data['endtime']
    #print("between_time", between_time)

    disabled = data['Weekends'] == False and data['Weekdays'] == False
    print("disabled is", disabled)
    
    weekday_rules = current_day in [0,1,2,3,4]
    #print("weekday_rules", weekday_rules)

    weekend_rules = current_day in [5,6]
    #print("weekend_rules", weekend_rules)
    
    if between_time and not disabled and weekday_rules or between_time and not disabled and weekend_rules:
        return True
    else:
        return False

data1 似乎可以正常工作：

# True weekend/weekdays and on start/end times 
condition_checker(data1,current_time,current_day)

返回

disabled is False
True

data2 似乎可以正常工作：

# True on Weekends and start/end times
condition_checker(data2,current_time,current_day)

返回

disabled is False
True

data3 似乎可以正常工作：

# False on times
condition_checker(data3,current_time,current_day)

返回

disabled is False
False

这是我的逻辑不起作用的地方，在disabled 上应该是错误的 data4 不工作

# False on disabled
condition_checker(data4,current_time,current_day)

返回

disabled is False
True

Answer 1

您正在将字符串与函数中的布尔值进行比较。我会更改字典以保存布尔值True/False，如下所示：

data1 = {'setpoint': '366', 'Weekdays': True, 'Weekends': True, 'starttime': '02:40', 'endtime': '22:40'}
data2 = {'setpoint': '366', 'Weekdays': False, 'Weekends': True, 'starttime': '02:40', 'endtime': '22:40'}
data3 = {'setpoint': '366', 'Weekdays': True, 'Weekends': False, 'starttime': '02:40', 'endtime': '03:40'}
data4 = {'setpoint': '366', 'Weekdays': False, 'Weekends': False, 'starttime': '02:40', 'endtime': '22:40'}

或者（不太可取，但也可以），您可以更改函数以检查 string 值：

def condition_checker(data,current_time,current_day):
    between_time = data['starttime'] <= current_time <= data['endtime']
    disabled = data['Weekends'] == "False" and data['Weekdays'] == "False"
    print("disabled is", disabled)
    
    weekday_rules = current_day in [0,1,2,3,4]
    weekend_rules = current_day in [5,6]
    
    if between_time and not disabled and weekday_rules or between_time and not disabled and weekend_rules:
        return True
    else:
        return False