从 CSV 文件读取时 Python 代码中的 ValueError 错误

Question

您好，我应该按照以下步骤操作。我已完成但收到此错误

文件“C:/Users/User/Desktop/question2.py”，第 37 行，在 jobtype_salary[li['job']] = int(li['salary'])

ValueError: int() 以 10 为底的无效文字：'SECRETARY 一个。将文件读入列表列表（14 行，5 列）

b.将列表的每一行转换为字典。键是：ename、job、salary、comm、dno。调用字典结果列表 dict_of_emp

c。显示表dict_of_emp，每行一行

d。对dict_of_emp进行如下计算：

D1。计算并打印 Richard 和 Mary 的收入（加上薪水和通讯）

D2 计算并显示支付给每种工作类型的工资总和（即支付给分析师的工资为 3500 + 3500= 7000）

D3。将部门 30 员工的工资加 5000。显示新表格

    import csv
    #Open the file in read mode
    f = open("employeeData.csv",'r')
    reader = csv.reader(f)
    #To read the file into list of lists we use list() method
    emps = list(reader)
    #print(emps)
    #Transform each row into a dictionary.
    dict_of_emp = [] #list of dictionaries
    for row in emps:
        d={}
        d['ename'] = row[0]
        d['job'] = row[1]
        d['salary']=row[2]
        d['comm']=row[3]
        d['dno']=row[4]
        dict_of_emp.append(d)
    print("*************************************************")
    #display the table dict_of_emp, one row per line.
    for li in dict_of_emp:
        print(li)
    print("*************************************************")
    #Incomes of Richard and Mary, to add salary and commision, first we need to cast them to integers.
    d1 = ['RICHARD','MARY']
    for li in dict_of_emp:
        if li['ename'] in d1:
            print('income of ', li['ename']," is ",int(li['salary']+li['comm']))
            
    print("*************************************************")
    #Sum of salaries based on type of job, dictionary is used so the job type is key 
    #and sum of salary is value
    jobtype_salary = {}
    for li in dict_of_emp:
        if li['job'] in jobtype_salary.keys():
            jobtype_salary[li['job']] += int(li['salary'])
        else:
            jobtype_salary[li['job']] = int(li['salary'])
    print(jobtype_salary)
    print("*************************************************")
    #Add 5000 to salaries of employees in department 30.
    for li in dict_of_emp:
        if li['dno']=='30':
            li['salary']=int(li['salary'])+5000
    for li in dict_of_emp:
        print(li)

这是 csv 作为图像：

Answer 1

我认为您的列的索引略有偏差。你做d['salary'] = row[2]，根据CSV，它对应于第三行，即人的位置（秘书，销售员）。如果您随后尝试将此字符串转换为整数，则会收到错误消息。

它会用这个来运行吗？

for row in emps:
        d={}
        d['ename'] = row[1]
        d['job'] = row[2]
        d['salary']=row[3]
        d['comm']=row[4]
        d['dno']=row[5]
        dict_of_emp.append(d)