sql查询计数先生已婚，未婚和女士已婚，未婚，其中性别=男性和性别=女性答案

【问题标题】：sql query for count gentlemen married,unmarried & ladies married,unmarried where gender=Male and gender =femalesql查询计数先生已婚，未婚和女士已婚，未婚，其中性别=男性和性别=女性
【发布时间】：2022-01-22 14:57:36
【问题描述】：

我正在使用 PostgreSQL。我要数数：

已婚先生未婚where gender='M'
已婚女士和未婚女士where gender='F'
已婚总数和未婚总数。

我只能执行已婚先生和未婚先生或已婚女士和未婚女士where gender=? 但是，我无法执行以下整个查询。所以，任何人都可以请给我有关以下代码的更正。

SELECT COUNT(CASE
               WHEN married = 'M' THEN
                1
             END) AS gentlemen_married WHERE gender = 'M',
       COUNT(CASE
               WHEN married = 'U' THEN
                1
             END) AS gentlemen_unmarried WHERE gender = 'M',
       COUNT(CASE
               WHEN married = 'M' THEN
                1
             END) AS ladies_married WHERE gender = 'F',
       COUNT(CASE
               WHEN married = 'U' THEN
                1
             END) AS ladies_unmarried WHERE gender = 'F',
       COUNT(*) AS married_COUNT WHERE married = 'M',
       COUNT(*) AS unmarried_COUNT WHERE married = 'U'
  FROM station
 WHERE group = 'abc';

【问题讨论】：

标签： sql postgresql-9.5

【解决方案1】：

我尝试了很多方法，最后，下面的代码对我有用：

SELECT Sum(CASE
             WHEN married = 'M'
                  AND gender = 'M' THEN 1
             ELSE 0
           END) AS gentlemen_married,
       Sum(CASE
             WHEN married = 'U'
                  AND gender = 'M' THEN 1
             ELSE 0
           END) AS gentlemen_unmarried,
       Sum(CASE
             WHEN married = 'M'
                  AND gender = 'F' THEN 1
             ELSE 0
           END) AS ladies_married,
       Sum(CASE
             WHEN married = 'U'
                  AND gender = 'F' THEN 1
             ELSE 0
           END) AS ladies_unmarried,
       Sum(CASE
             WHEN married = 'M' THEN 1
             ELSE 0
           END) AS married_count,
       Sum(CASE
             WHEN married = 'U' THEN 1
             ELSE 0
           END) AS unmarried_count
FROM   station
WHERE  rrcode = 'abc';

【讨论】：