如何纠正oracle中的分页？

Question

我正在向用户显示他/她接受了多少表格，为此我在 php 中使用了分页。数据从 oracle 数据库中获取并显示在表中。我正在使用分页，但是当我转到下一页时，它显示上一条记录的新记录未显示。

<table>
<tbody>
    <?php
    include('connect.php');
    $user_name = $_SESSION['username'];
    $sql = oci_parse($conn,"select * from userM where user_name = '$user_name'");
    $result = oci_execute($sql);

    while(($row = oci_fetch_array($sql,OCI_BOTH)) != false ){
        $approvedBy = $row[1];
    }
    if(!isset($_GET['page'])){
        $_GET['page'] = 0;
    }else{
        // Convert the page number to an integer
        $_GET['page'] = (int)$_GET['page'];
    }
    $varPage = $_GET['page'];
    if($varPage == "" || $varPage == "1"){
        $page1 = 0;
    }else{
        $page1 = ($varPage*6)-6;
    }
    $approvedBy = strtoupper($approvedBy);

    $sql = oci_parse($conn,"SELECT * FROM formC where UPPER(approvedBy) = '$approvedBy' AND rownum < 7");
    oci_execute($sql);

    while(($row = oci_fetch_array($sql,OCI_BOTH)) != false )  {
        $accountingNo = $row[0];
        ?>
        <tr>
            <td style="color:black"><?php echo  $row[0] ?></td>
            <td style="color:black"><?php echo  $row[1] ?></td>
            <td style="color:black"><?php echo  $row[2]  ?></td>
            <td style="color:black"><?php echo $row[3]?></td>
            <td style="color:black"><?php echo $row[4] ?></td>
            <td style="color:black"><?php echo $row[7] ?></td>         
        </tr>
        <?php 
    }
    ?>
</tbody>
</table>

<?php
$sql1 = oci_parse($conn,"SELECT * FROM formC where UPPER(approvedBy) = '$approvedBy'");
oci_execute($sql1);
$count = oci_fetch_all($sql1,$abc);
$a=$count/6;
$a = ceil($a);

for($b=1;$b<=$a;$b++){
    ?>
    <a href="approvedList.php?page=<?php echo $b?>" style="text-decoration;align:center: none;" class="btn btn-success "><?php echo $b." "; ?></a>
    <?php
}
oci_close($conn);
?>
</div> 

Answer 1

这在The Underground PHP and Oracle Manual，第 181 页中进行了解释：

Oracle8i 及更高版本的规范分页查询在http://asktom.oracle.com 上给出：

select *
  from ( select a.*, rownum as rnum
         from (YOUR_QUERY_GOES_HERE -- including the order by) a
         where rownum <= MAX_ROW )
  where rnum >= MIN_ROW

这里，MIN_ROW 是行号 第一行，MAX_ROW 是要返回的最后一行的行号。

甚至还有一个完整的示例脚本：

<?php
$c = oci_connect('hr', 'welcome', 'localhost/XE');
$mystmt = "select city from locations order by city";
$minrow = 4; // row number of first row to return
$maxrow = 8; // row number of last row to return
$pagesql = "select *
            from ( select a.*, rownum as rnum
                   from ( $mystmt ) a
                   where rownum <= :maxrow)
            where rnum >= :minrow";
$s = oci_parse($c, $pagesql);
oci_bind_by_name($s, ":maxrow", $maxrow);
oci_bind_by_name($s, ":minrow", $minrow);
oci_execute($s);
oci_fetch_all($s, $res);
var_dump($res);
?>

---

编辑：

作为mentioned by Christopher Jones，在Oracle >=12.1 中，使用offset clause 有一种更简洁的方法：

select *
from mytable
order by myfield
offset X rows fetch next Y rows only

Answer 2

我不是预言家，但我不建议您选择所有行并计算它们，我认为最好使用此代码来计算行数：

$sql1 = oci_parse($conn,"SELECT COUNT(*) FROM formC where UPPER(approvedBy) = '$approvedBy'");
    oci_execute($sql1);
$count = oci_fetch_all($sql1,$abc);
$a=$count/6;

oracle count documentation

要解决您的问题，请参阅此问题：How do I limit the number of rows returned by an Oracle query after ordering?

您计算当前页面并将其保存在$page1，但没有在您的查询中使用它！！