用户 10085 和当前进程都没有 android.permission.READ_PHONE_STATE

Question

我已经更新了目标 sdk 版本 27，并且我已在 READ_PHONE_STATE. 的 manifest 中给予许可，但我的应用程序在 utils.java 上仍然崩溃

 deviceId = TelephonyMgr.getDeviceId(); 

在这条线上，我还要求运行时许可，但问题还是一样

private void RequestMultiplePermission() {

        // Creating String Array with Permissions.
        ActivityCompat.requestPermissions(LoginActivity.this, new String[]
                {
                        CALL_PHONE,
                        READ_PHONE_STATE
                }, RequestPermissionCode);

    }
    public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
        switch (requestCode) {

            case RequestPermissionCode:

                if (grantResults.length > 0) {

                    boolean GetCallPermission = grantResults[0] == PackageManager.PERMISSION_GRANTED;
                    boolean GetReadphoneper = grantResults[1] == PackageManager.PERMISSION_GRANTED;

                    if (GetCallPermission && GetReadphoneper) {

                        Toast.makeText(LoginActivity.this, "Permission Granted", Toast.LENGTH_LONG).show();
                    }
                    else {
                        ///Toast.makeText(Login.this,"Permission Granted",Toast.LENGTH_LONG).show();
                    }
                }
                break;
        }
    }

在这一行中它会崩溃 deviceId = TelephonyMgr.getDeviceId();

public static String getUniqueDeviceId(Context context) {
        String deviceId;
        // 1 compute IMEI
        final TelephonyManager TelephonyMgr = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
        if (ActivityCompat.checkSelfPermission(context, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {

        }
        deviceId = TelephonyMgr.getDeviceId(); // Requires // READ_PHONE_STATE
        if (deviceId == null) {
            // 2 android ID - unreliable
            deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
        }
        if (deviceId == null) {
            Random r = new Random();
            deviceId = String.valueOf((r.nextInt() + r.nextInt()));
        }

        e(deviceId);
        return deviceId;
    }

Answer 1

用这个解决了::

 deviceId = Settings.Secure.getString(context.getContentResolver(),
                InstanceID.getInstance(context).getId());