在 Python 井字游戏中输入“X/O”

Question

我正在尝试为井字游戏编写代码，但在模板上打印“X”时遇到困难...我的板已设置为具有 x 轴和 y 轴，我正在尝试要求用户输入 x 值和 y 值并使用该 x 和 y 值在板的正确区域打印“X”...有人可以帮我吗？

def printboard(board):
    print("     0   1   2  ")
    print()
    print(" 0   " + board[0][0] + " | " + board[0][1] +" | " + board[0][2] +" ")
    print("    ---+---+---")
    print(" 1   " + board[1][0] + " | " + board[1][1] +" | " + board[1][2] +" ")
    print("    ---+---+---")
    print(" 2   " + board[2][0] + " | " + board[2][1] +" | " + board[2][2] +" ")
    print()


def isBoardFull(board):
    print(board)
    if board[0][0]== board[0][1] == board[0][2] != " "\
            or board[1][0]== board[1][1] == board[1][2] !=" "\
            or board[2][0]== board[2][1] == board[2][2] !=" "\
            or board[0][0]== board[1][0] == board[2][0] != " "\
            or board[0][1]== board[1][1] == board[2][1] !=" "\
            or board[0][2]== board[1][2] == board[2][2] !=" "\
            or board[0][0]== board[1][1]== board[2][2] !=" "\
            or board [0][2]== board[1][1]== board[2][0] !=" ":
        print("board is full")
        return isBoardFull==True
    else:
        return isBoardFull==False

def isHorizontalTicTacToe(board):
        if board[0][0]== board[0][1] == board[0][2] != " "\
        or board[1][0]== board[1][1] == board[1][2] !=" "\
        or board[2][0]== board[2][1] == board[2][2] !=" ":
            print("You won!")
#isHorizontalTicTacToe([[" "," ", " "],["X", "X", "X"],[" ", " ", " "]])

def isVerticalTicTacToe(board):
    if board[0][0]== board[1][0] == board[2][0] != " "\
    or board[0][1]== board[1][1] == board[2][1] !=" "\
    or board[0][2]== board[1][2] == board[2][2] !=" ":
        print("You won!")
#isVerticalTicTacToe([[" ","X", " "],[" ", "X", " "],[" ", "X", " "]])    




def isDiagonalTicTacToe(board):
    if board[0][0]== board[1][1]==board[2][2] !=" "\
        or board [0][2]== board[1][1]==board[2][0] !=" ":
            print("You won!")
#isDiagonalTicTacToe([[" "," ", "X"],[" ", "X", " "],["X", " ", " "]])





def playerMove(board):
    printboard([[" "," ", " "],[" ", " ", " "],[" ", " ", " "]])
    print("Player 1 will be X")
    print("Player 2 will be O")
    playerOneH=int(input("Player One, enter X coordinates of move "))
    playerOneV=int(input("Player One, enter Y coordinates of move "))
    printboard[playerOneH,playerOneV]="X"
playerMove(1)

def playOneGame():
    printboard([[" "," ", " "],[" ", " ", " "],[" ", " ", " "]])
    #playerOneH=input("Player One, enter a horizontal coordinates for the first move ")
    #playerOneV=input("Now enter a vertical coordinate for the first move ")

#playOneGame()

def main():
    # this function should contain a loop that runs playOneGame until the user says he does not want to play anymore
    pass

Answer 1

就您的错误而言，在您的 printBoard 函数中，您正在为函数分配一个值，但您想将其分配给数据结构（板）

printboard[playerOneH,playerOneV]="X"

应该是

board[playerOneH][playerOneV]="X"
printboard(board)

Answer 2

仔细考虑每个函数调用应该做什么，例如：它应该获取什么参数，以及它应该返回什么。 （并且，如果它应该创建输出或读取输入）。

例子：

def playerMove(board):

什么是板子？我有点期待它是井字游戏的代表，例如三个列表的列表，每个列表三个字符。

但是你用它来调用它

playerMove(1)

这是一个整数，不是棋盘表示。

例如，您可能决定该函数应允许单个玩家在固定棋盘上进行单步移动。然后你会像这样定义它：

def playerMove(board, player):
    x = int(input("Player {}, please enter x: ".format(player)))
    y = int(input("Player {}, please enter y: ".format(player)))
    # Check whether x, y is a valid choice, that is: not yet taken
    board[x][y] = 'X' if player == 1 else 'O'

因为列表是可变的，所以板子会更新。然后你需要某种循环来玩游戏：

def playGame():
    board = [[' ', ' ', ' '], [' ', ' ', ' '], [' ', ' ', ' ']]
    finished = False
    player = 1
    while not finished:
        printboard(board)
        playerMove(board, player)
        # Check for win/end, set finished accordingly
        player = 3 - player # Switches between 1 and 2