Python - 井字游戏答案

【问题标题】：Python - TicTacToePython - 井字游戏
【发布时间】：2021-01-26 19:33:47
【问题描述】：

在这个问题中，我必须在 python 中创建一个将在终端中运行的井字游戏。这是一个 2 人游戏，如果任何玩家按照井字游戏规则获胜，则必须打印获胜者 = 玩家 1/2。

当我在对角线上有三个 0 或 1 时，我得到了一个获胜者声明，但在其他两种情况下（水平和垂直）我没有得到获胜者

请帮忙找出我的代码中的错误

import numpy as np

def create_board():
    return (np.array([[0, 0, 0],
                      [0, 0, 0],
                      [0, 0, 0]]))


def coordinates(board, player):
    i, j, cn = (-1, -1, 0)
    while (i > 3 or i < 0 or j < 0 or j > 3) or (board[i][j] != 0):
        if cn > 0:
            print("Wrong Input! Try Again")
        print("Player {}'s turn".format(player))
        i = int(input("x-coordinates: "))
        j = int(input("y-coordinates: "))
        i = i - 1
        j = j - 1
        cn = cn + 1
    board[i][j] = player
    return board


def row_win(board, player):
    for x in range(len(board)):
        win = True

        for y in range(len(board)):
            if board[x, y] != player:
                win = False
                continue
    return win


def col_win(board, player):
    for x in range(len(board)):
        win = True

        for y in range(len(board)):
            if board[y][x] != player:
                win = False
                continue

    return win


def diag_win(board, player):
    win = True
    y = 0
    for x in range(len(board)):
        if board[x][x] != player:
            win = False
    if win:
        return win
    win = True
    if win:
        for x in range(len(board)):
            y = len(board) - 1 - x
            if board[x][y] != player:
                win = False
    return win


def evaluate(board):
    winner = 0

    for player in [1, 2]:
        if (row_win(board, player) or
                col_win(board, player) or
                diag_win(board, player)):
            winner = player

    if np.all(board != 0) and winner == 0:
        winner = -1
    return winner


def play_game():
    board, winner, counter = create_board(), 0, 1
    print(board)
    while winner == 0:
        for player in [1, 2]:
            board = coordinates(board, player)
            print("Board after " + str(counter) + " move")
            print(board)
            counter += 1
            winner = evaluate(board)
            if winner != 0:
                break
    return winner

print("Winner is: " + str(play_game()))

【问题讨论】：

continue 应该是break。
numpy 对于像 3x3 数组这样简单的东西来说是一个非常严重的依赖项。您使用的唯一 NumPy 特定功能是np.all，当board 是一个普通的嵌套列表时，您可以将其替换为all(x != 0 for row in board for x in row)。

标签： python arrays numpy pypi tic-tac-toe

【解决方案1】：

假设这是董事会：

x x x 
o o x
x o o

您的row_win 检查第一行，win 仍然是True。然后继续检查第二行，win 设置为False。在最后一行之后，该函数最终报告玩家没有赢，即使它赢了。

要解决此问题，请将您的 row_win 和 col_win 更改为以下内容：

def row_win(board, player):
    for row in board:
        if all([cell == player for cell in row]):
            return True
    return False

如果一行的所有单元格都等于玩家，则玩家获胜。如果没有一行的所有单元格都等于玩家，则玩家没有获胜。

【讨论】：