从熊猫日期列中减去当前时间

Question

我有一个类似

的熊猫数据框

x = pd.DataFrame(['05/06/2015 00:00', '22/06/2015 00:00', None], columns=['myDate'])

我想找出myDate 列中的日期与当前日期之间的天数。我怎样才能做到这一点？我尝试了以下但没有太大成功

pd.to_datetime(x['myDate']) - pd.datetime.now().date()

Answer 1

以下对我有用：

In [9]:

df = pd.DataFrame(['05/06/2015 00:00', '22/06/2015 00:00', None], columns=['myDate'])
df['myDate']= pd.to_datetime(df['myDate'], errors='coerce')
df
Out[9]:
      myDate
0 2015-05-06
1 2015-06-22
2        NaT
In [10]:

df['diff'] = df['myDate'] - pd.Timestamp.now().normalize()
df
Out[10]:
      myDate    diff
0 2015-05-06  9 days
1 2015-06-22 56 days
2        NaT     NaT

你的版本也是这样：

In [13]:

df['diff'] = df['myDate'] - pd.Timestamp.now().normalize()
df
Out[13]:
      myDate    diff
0 2015-05-06  9 days
1 2015-06-22 56 days
2        NaT     NaT

更紧凑的版本：

In [15]:

df = pd.DataFrame(['05/06/2015 00:00', '22/06/2015 00:00', None], columns=['myDate'])
df['diff']= pd.to_datetime(df['myDate'], errors='coerce') - pd.Timestamp.now().normalize()
df
Out[15]:
             myDate    diff
0  05/06/2015 00:00  9 days
1  22/06/2015 00:00 56 days
2              None     NaT