根据集合大小实例化不同派生类的更简洁方法？

Question

我一直在尝试制作一种灵活的方法，它将用不同的派生对象填充单个集合。我希望此方法还可以基于类型集合扩展其功能。问题是，为了让它看起来超级棒，我需要用一个类型替换一个显式的强制转换类名。我读到 this question here 无法使用编译时未知的类名进行强制转换。

我的问题是，您将如何重构此代码以减少重复并根据集合大小灵活处理？

public struct POSSIBLE_OUTPUTS
{        
    public static Type MarekType { get; private set; }
    public static Type HawkingType { get; private set; }
    public static Type GLADOSType { get; private set; }
    public static List <Type> AllOptions { get; private set; }

    static POSSIBLE_OUTPUTS()
    {
        MarekType = typeof (MarekVoice);
        HawkingType = typeof (HawkingVoice);
        GLADOSType = typeof (GLADOSVoice);
        AllOptions = new List <Type>();
        AllOptions.Add (MarekType);
        AllOptions.Add (HawkingType);
        AllOptions.Add (GLADOSType);
    }
} 

Speeches = new List <SentenceFactory>();

for (int i = 0; i < POSSIBLE_OUTPUTS.AllOptions.Count; i++)
{
    for (int k = 0; k < TOTAL_SPEECHES; k++)
    {     
        if (POSSIBLE_OUTPUTS.AllOptions[i] == POSSIBLE_OUTPUTS.MarekType)
        {
            Speeches.Add (Activator.CreateInstance (POSSIBLE_OUTPUTS.AllOptions[i]) as MarekVoice);                                       
        }

        else if (POSSIBLE_OUTPUTS.AllOptions[i] == POSSIBLE_OUTPUTS.HawkingType)
        {
            Speeches.Add (Activator.CreateInstance (POSSIBLE_OUTPUTS.AllOptions[i]) as HawkingVoice);                                       
        }

        else if (POSSIBLE_OUTPUTS.AllOptions[i] == POSSIBLE_OUTPUTS.GLADOSType)
        {
            Speeches.Add (Activator.CreateInstance (POSSIBLE_OUTPUTS.AllOptions[i]) as GLADOSVoice);                                       
        }    
    }                
}

Answer 1

由于它们都派生自 SentenceFactory，因此您可以将所有 if 和 cast 替换为 just

Speeches.Add(Activator.CreateInstance (POSSIBLE_OUTPUTS.AllOptions[i]) as SentenceFactory);