【发布时间】:2021-10-28 03:38:03
【问题描述】:
我有这个 UML 图,我已经编写了下面的代码,但我正在努力处理错误消息
但是,在编译和链接时,我得到了一个错误
/tmp/cc9oQaPX.o: In function `main':
main.cpp:(.text+0x8c): undefined reference to `Fish::Fish(std::string)'
main.cpp:(.text+0xe5): undefined reference to `Cat::Cat(std::string)'
main.cpp:(.text+0x116): undefined reference to `Fish::Fish()'
main.cpp:(.text+0x158): undefined reference to `Cat::Cat()'
collect2: error: ld returned 1 exit status
#include <iostream>
using namespace std;
class Animal // define base class
{
protected:
int legs; // base class properties
public:
Animal(int legNumbers) // set values of leg
{
legNumbers = legs; // set values of leg
}
virtual void eat() = 0; // method of base class
virtual void walk() {}; // method of base class
};
class Pet // define the pet class
{
protected:
string name; // set properties of pet class
public:
virtual string getName(); // define method
virtual string setName(string name); // set name values
virtual void play() // define play method
{
cout << " garfield is playing now." << endl; // out values
}
};
class Spider :public Animal //child class inherit base class
{
public:
Spider() :Animal(8) // spider class inherit animal class
{
cout << "animals with " << legs << " legs is walking. " << endl;
}
virtual void eat() // define virtual method
{
cout << "spider is eating now. " << endl;
}
};
class Cat :public Pet, public Animal // cat inherit two classes
{
public:
Cat(string name); // set name method
Cat();
virtual void play() // define method
{
cout << name << " is playing now. " << endl;
}
virtual void eat(); // define method here
};
class Fish : public Pet, public Animal // fish inherit two method
{
public: // define public members
Fish(string name);
Fish();
virtual void play()
{
cout << name << " is playing now. " << endl;
}
virtual void eat(); // method here
void walk()
{
cout << " Fish cannot walk " << endl; // output the values
}
};
string Pet::getName() // get name value from parent class
{
return string();
}
string Pet::setName(string name)
{
return string();
}
int main(int argc, char* argv[]) // define main method
{
Fish* f = new Fish("Jaws");
Cat* c = new Cat("Tenkir");
Animal *a = new Fish();
Animal* e = new Spider();
Pet* p = new Cat();
f->play();
c->play();
e->eat();
e->walk();
a->walk();
p->play();
return 0;
}
【问题讨论】:
-
您对构造函数有未定义的引用。您需要定义它们。
-
@cigien 请检查我的代码并告诉我如何解决此错误消息?
-
例如,您声明了
Cat(string name);,但从未定义它。你需要这样做,仅此而已。 -
@cigien 非常感谢您回答我这个问题,非常感谢您..
-
糟糕,这当然是重复的问题:stackoverflow.com/questions/68963268/… 所以请不要以多个用户的身份发布问题,尤其是当他们关闭时。
标签: c++ c++11 visual-c++ c++14