【发布时间】：2018-02-05 03:40:06
【问题描述】：
试图制作一个粗略的功能/联系人列表。用户登录后被带到此页面：
通过单击编辑功能，我希望将用户带到允许他们编辑联系方式的页面。目前正在努力使链接功能正常。
链接照片是我的 /view 文件。看起来像这样：
<?php
session_start();
if(isset($_SESSION['u_uid'])){
$uid = $_SESSION['u_id'];
require_once('connect.php');
$ReadSql = "SELECT * FROM `contact` WHERE users_id=$uid ORDER BY Name";
$res = mysqli_query($connection, $ReadSql);
?>
<head>
<title>Motoko</title>
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet"
href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<!-- Latest compiled and minified JavaScript -->
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js">
</script>
</head>
<body>
<div class="container">
<div class="row">
<table class="table">
<tr>
<th><strong>Name</strong></th>
<th><strong>Company</strong></th>
<th><strong>Title</strong></th>
<th><strong>Phone</strong></th>
<th><strong>Email</strong></th>
<th><strong>Address</strong></th>
<th><strong>Extras</strong></th>
</tr>
<?php
while($r = mysqli_fetch_assoc($res)){
?>
<tr>
<td><?php echo $r['Name']; ?></td>
<td><?php echo $r['Company']; ?></td>
<td><?php echo $r['Title']; ?></td>
<td><?php echo $r['Phone']; ?></td>
<td><?php echo $r['Email']; ?></td>
<td><?php echo $r['Address']; ?></td>
<td><a href="crud/update.php?id=<?php echo $r['id'] ?>">Edit</a></td>
<td><input type="button" onClick="deleteme(<?php echo $r['u_uid']; ?>)" name="Delete" value="Delete"></td>
</tr>
<!-- Javascript function for deleting data -->
<script language="Javascript">
function deleteme(delid)
{
if(confirm("Are you sure you want to Delete?")){
window.location.href='crud/delete.php';
}
}
</script>
<?php } ?>
</table>
</div>
</body>
</html>
<?php
}else{
header("Location: http://motoko.sorainsurance.com.au");
}
?>
这会将它们带到 /update 文件。开头是：
<?php
error_reporting();
require_once('connect.php');
$id = $_GET['id'];
$SelSql = "SELECT * FROM `contact` WHERE id=$id";
$res = mysqli_query($connection, $SelSql);
$r = mysqli_fetch_assoc($res);
if(isset($_POST) & !empty($_POST)){
$name = mysqli_real_escape_string($connection,$_POST['name']);
$comp = mysqli_real_escape_string($connection,$_POST['comp']);
$title = mysqli_real_escape_string($connection,$_POST['title']);
$phone = mysqli_real_escape_string($connection,$_POST['urstel']);
$email = mysqli_real_escape_string($connection,$_POST['email']);
$location = mysqli_real_escape_string($connection,$_POST['location']);
$UpdateSql = "UPDATE `contact` SET Name='$name', Company='$comp',
Title='$title', Phone='$phone', Email='$email', Address='$location' WHERE id=$id";
$res = mysqli_query($connection, $UpdateSql);
if($res){
echo $smsg = "Successfully updated data.";
echo header('location: view.php');
}else{
echo $fmsg = "Failed to update data.";
}
}
知道为什么错误不断弹出吗？如此困惑和努力进步:(
非常感谢！
【问题讨论】：
-
抱歉，每当出现 404 错误时，您可以在浏览器中发布链接吗？
-
404表示该页面不存在。我猜您在名为crud的文件夹中没有名为delete.php的文件。除此之外，您的脚本容易受到SQL injection 的攻击，您的括号不会与您的if条件对齐，并且在调用@ 之前您也不能将any 输出到DOM 987654330@（它本身不应该有echo）。
标签： php mysql error-handling edit crud