【发布时间】:2017-10-14 15:50:13
【问题描述】:
我想查看复选框作为类别的 id 并取决于下拉选择有人可以帮助我
下拉选择运行良好,但 onchange 不起作用,如果我得到依赖于选择类别的子类别,如何在 mysql 数据库中插入多复选框
' 我的观点是
echo '<div class="control-group">';
echo '<label for="category_id" class="control-label">category</label>';
echo '<div class="controls">';
//echo form_dropdown('category_id', $options_category, '', 'class="span2"');
$js = 'id="category_sub" onChange="some_function();"';
echo form_dropdown('category_id', $options_category, set_value('category_id'), 'class="span2" id="category_id"',$js);
echo '</div>';
echo '</div">';
if( isset($_POST['category_id']) != ''){echo '<div class="control-group" id="category_sub"></div>';
foreach ($services as $row){
$id = $row['ID'] ; $options_sub_category = $row['Name_En'];
// echo $options_sub_category ;
//echo form_checkbox($options_sub_category, $options_sub_category, TRUE, 'class="span2" id="services"');
echo '<input type ="checkbox" name="services" id ="services" value="'. echo $id .'"> '. echo $options_sub_category ; .'';
}
}
我的控制者是
公共函数add() {
if(isset($_POST['category_id']) && $this->input->post('category_id')!=null){
$id = $this->input->post('category_id');
$data ['services'] = $this->service_model->get_services($id);
}
//if save button was clicked, get the data sent via post
//fetch categorys data to populate the select field
$data['categorys'] = $this->category_model->get_category();
//load the view
$data['main_content'] = 'admin/company/add';
$this->load->view('includes/template', $data); }
我的模型是
公共函数 get_services($id) {
$this->db->select('*');
$this->db->where('category_id', $id);
$this->db->from('service');
$query = $this->db->get();
return $query->result_array(); }
【问题讨论】:
-
从 foreach 获取的值 ($services as $row) { $options_sub_category[$row['ID']] = $row['Name_Ar']; }
-
请分享完整代码
-
你在 $options_sub_category 变量中传递了什么?您是否在 $options_sub_category 中传递数组?
-
是的,传递数组
标签: php codeigniter