【发布时间】:2015-04-21 14:34:17
【问题描述】:
尝试仅显示与表单中选择的下拉框匹配的<div>。
表单是使用 Form 类生成的,选项位于数据库的表中(race、class)。最后是这样的:
<form action="" method="post" name="create" target="_top">
<fieldset>
<ul class="create">
<li>
<label class="label" for="character_name">Character Name:</label>
<input class="text" type="text" name="character_name" id="character_name" />
</li>
<li>
<label class="label" for="character_gender">Gender:</label>
<select class="character_gender select" name="character_gender" id="character_gender">
<option class="option" value="1">Female</option>
<option class="option" value="2">Male</option>
</select>
</li>
<li>
<label class="label" for="character_race">Character Race:</label>
<select class="character_race select" name="character_race" id="character_race">
<option class="option" value="1">Goblin</option>
<option class="option" value="2">Human</option>
<option class="option" value="3">Undead</option>
</select>
</li>
<li>
<label class="label" for="character_class">Character Class:</label>
<select class="character_class select" name="character_class" id="character_class">
<option class="option" value="1">Warrior</option>
<option class="option" value="2">Wizard</option>
</select>
</li>
<li>
<input class="submit-create-character" type="submit" name="create_character" value="Create" />
</li>
</ul>
</fieldset>
</form>
我的控制器调用 Avatar、CharacterClass、Race 类。
我的avatar 表有将ID 存储到race.id 和class.id table.id_column 的列。
# Get all the avatars in the `avatars` table.
$avatars=$avatar_obj->getAllAvatars();
foreach($avatars as $avatar)
{
# Get the image information from the database, and set them to data members.
$avatar_obj->getThisImage($avatar->image_id);
# Set the Image object to a variable.
$image_obj=$avatar_obj->getImageObj();
# Set the image file name to a variable.
$image_file_name=$image_obj->getFileName();
# Get the class info from the database and set the data members.
$class_obj->getThisCharacterClass($avatar->class_id);
# Get the race info from the database and set the data members.
$race_obj->getThisRace($avatar->race_id);
echo '<div class="class-info">',
'<div class="avatar-box">',
'<img src="'.IMAGES_PATH.$image_file_name.'" alt="'.$image_obj->getTitle().'" />',
'</div>';
echo $race_obj->getDescription().'<br>';
echo $class_obj->getDescription();
echo '</div>';
}
这显示了一堆<div>的:
<div class="class-info">
<div class="avatar-box"><img src="Female.Goblin.Warrior.gif" alt="Female Warrior" /></div>
Goblin description.<br>
Warrior Description
</div>
<div class="class-info">
<div class="avatar-box"><img src="Male.Goblin.Warrior.gif" alt="Male Warrior" /></div>
Goblin description.<br>
Wizard Description
</div>
<div class="class-info">
<div class="avatar-box"><img src="Female.Human.Warrior.gif" alt="Female Warrior" /></div>
Human description.<br>
Warrior Description
</div>
<div class="class-info">
<div class="avatar-box"><img src="Male.Human.Warrior.gif" alt="Male Warrior" /></div>
Human description.<br>
Wizard Description
</div>
<div class="class-info">
<div class="avatar-box"><img src="Female.Undead.Warrior.gif" alt="Female Warrior" /></div>
Undead description.<br>
Warrior Description
</div>
<div class="class-info">
<div class="avatar-box"><img src="Male.Undead.Warrior.gif" alt="Male Warrior" /></div>
Undead description.<br>
Wizard Description
</div>
(还有更多)
我被困在这一点上。我不确定如何找出 jQuery 来隐藏/显示正确的 <div>。
【问题讨论】:
-
性别选择有什么问题?
-
其实没什么。我什至不需要
avatar表中的gender_id,我有image_id。我想多了。只需要 jQuery 就可以了。
标签: javascript php jquery html mysql