如何自动装配 CrudRepository 的实现实例

Question

我使用 Spring Boot 构建了一个应用程序。主类是这样的

@Configuration
@ComponentScan
@EnableAutoConfiguration
public class TheApplication {

    public static void main(String[] args) {
        SpringApplication.run(TheApplication.class, args);
    }
}

然后我有一个定义存储库的接口。

package com.application.repositories

@Repository
public interface InstrumentRepository extends CrudRepository<Instrument, String> {

    public List<Instrument> findByPartnerAndUid(Partner partner, String uid);
}

在 REST 控制器中，我定义了类：

@RestController
@RequestMapping("/instrument")
public class InstrumentRestController {

    @Autowired
    private InstrumentRepository instrumentRepository;

    @RequestMapping(value = "/find_all", method = RequestMethod.GET)
    Collection<Instrument> findAllInstrument () {
        return (Collection<Instrument>) this.instrumentRepository.findAll();
    }

    ...
}

从这里开始，如果我运行应用程序并访问http://localhost:8080/instrument/find_all，则会创建 InstrumentRepository 的 bean。

---

而且，这就是我遇到的问题。 有一个定义 bean 的配置：

<context:annotation-config />
<bean id="service"
        class="com.application.AccountService"></bean>
<jpa:repositories base-package="com.application.repositories"></jpa:repositories>

AccountService 类：

public class AccountService {
    @Autowired
    private InstrumentRepository instrumentRepository;

    Collection<Instrument> getAllAccountInstrument(accountId) {
        this. instrumentRepository.findAllInstrumentByAccountId(accountId);
    }
}

和 REST 控制器：

@RestController
@RequestMapping("/account")
public class AccountRestController {

    @RequestMapping(value = "/{accountId}/find_instrument", method = RequestMethod.GET)
    Collection<Instrument> findAccountInstrument (@PathVariable String accountId) {

        ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("account.xml");
        AccountService service = (AccountService) context.getBean("service");
        service.getAllAccountInstrument(accountId);
        context.close();
    }

    ...
}

但是，当我访问/account/100/find_instrument 时，我得到了错误

org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'entityManagerFactory' is defined

---

编辑

这是我的数据库配置 应用程序.properties

# Database
spring.datasource.url= jdbc:postgresql://localhost:5432/appdb
spring.datasource.username=postgres
spring.datasource.password=postgres
spring.jpa.hibernate.ddl-auto=create

hibernate.properties

hbm2ddl.auto = create
hibernate.dialect = org.hibernate.dialect.PostgreSQLDialect
hibernate.show_sql = true

Answer 1

您的 Config 类中缺少完整的数据库配置。 试试这个例子：

@Bean
public DataSource dataSource() {
DriverManagerDataSource dataSource = new DriverManagerDataSource();
dataSource.setDriverClassName("org.hsqldb.jdbc.JDBCDriver");
dataSource.setUrl("jdbc:hsqldb:mem:testdb");
dataSource.setUsername("sa");
dataSource.setPassword("");
return dataSource;
}

@Bean
public EntityManager entityManager() {
return entityManagerFactory().getObject().createEntityManager();
}

@Bean
 public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
 LocalContainerEntityManagerFactoryBean em = new     LocalContainerEntityManagerFactoryBean();
em.setDataSource(dataSource());
em.setPackagesToScan("package.where.your.entites.like.CustSys.are.stored");
return em;
 }

根据entitymanagerfactory-is-defined

Answer 2

如果使用spring boot，必须在application.properties文件中添加数据库配置

例如mysql

spring.datasource.url=jdbc:mysql://localhost/yourdatabaseName
spring.datasource.username=youruserName
spring.datasource.password=yourPassword
spring.datasource.driver-class-name=com.mysql.jdbc.Driver

这里所有的属性 http://docs.spring.io/spring-boot/docs/current/reference/htmlsingle/#common-application-properties