计算没有星期六的下一个日期

Question

我想计算卡车在星期六（但不是星期日）静止不动的交货日期 如果交货时间是两天，我在星期五下订单，货物应该在星期一（星期日+星期一）到达。以下内容很好，但不包括星期日：

df['LEV'] = dat + df['Leadtime'].map(pd.tseries.offsets.BusinessDay)

我想做这样的事情。但它不起作用：

df['LEV'] = dat + df['Leadtime'].map(pd.tseries.offsets.CustomBusinessDay(weekmask = 'Mon Tue Wed Thu Fri Sun'))

地点：

2021-05-14 00:00:00
<class 'datetime.datetime'>
<class 'pandas.core.series.Series'>

谢谢

编辑： 小例子：

from datetime import datetime
DatToday = datetime.fromisoformat('2022-01-13')
data = {'Article': ['A1', 'A2'], 'LeadTime': [2, 6], 'DateToday': 
[DatToday,DatToday]}    
df = pd.DataFrame(data)  


df['Delivery_Day'] = DatToday + df['LeadTime'].map(pd.tseries.offsets.BusinessDay)

当前结果：

Article    LeadTime  DateToday     Delivery_Day
0     A1    2        2022-01-13    2022-01-17
1     A2    6        2022-01-13    2022-01-21

想要的结果：

Article    LeadTime  DateToday     Delivery_Day
0     A1    2        2022-01-13    2022-01-16
1     A2    6        2022-01-13    2022-01-20

即没有星期日的工作日。

错误信息：

~\Anaconda3\lib\site-packages\pandas\core\series.py in apply(self, func, 
convert_dtype, args, **kwds)
4198             else:
4199                 values = self.astype(object)._values
-> 4200                 mapped = lib.map_infer(values, f, 
convert=convert_dtype)
4201 
4202         if len(mapped) and isinstance(mapped[0], Series):

pandas\_libs\lib.pyx in pandas._libs.lib.map_infer()

pandas\_libs\tslibs\offsets.pyx in 
pandas._libs.tslibs.offsets.BaseOffset.__call__()

pandas\_libs\tslibs\offsets.pyx in 
pandas._libs.tslibs.offsets.apply_wraps.wrapper()

ApplyTypeError: 

Answer 1

您需要将您的CustomBusinessDay乘以天数：

cbd = pd.tseries.offsets.CustomBusinessDay(weekmask='Mon Tue Wed Thu Fri Sun')

df['Delivery_Day'] = DatToday + df['LeadTime'] * cbd

输出：

  Article  LeadTime  DateToday Delivery_Day
0      A1         2 2022-01-13   2022-01-16
1      A2         6 2022-01-13   2022-01-20