计算日期范围内的星期六和星期日的数量 - oracle [重复]答案

【问题标题】：Count the no of saturdays and sundays in date range - oracle [duplicate]计算日期范围内的星期六和星期日的数量 - oracle [重复]
【发布时间】：2014-08-20 08:25:17
【问题描述】：

我有两个参数（start_Date,end_Date）来自 table1

我正在尝试计算日期范围内的星期六和星期日的数量

star_Date=8/20/2014 13:52
end_Date=8/28/2014 13:52

结果应该是这样的

Start_Date        end_date          No_of_leaves 
8/20/2014 13:52   8/28/2014 13:52       2

更新部分

SELECT retouch_req_time,retouch_submit_time,(
        SELECT Count(*) FROM (SELECT To_char(start_date + ( LEVEL - 1 ), 'fmday') dt 
        FROM (WITH t AS (SELECT To_date (retouch_req_time, 'MM/DD/YYYY HH24:MI') start_date, To_date (retouch_submit_time, 'MM/DD/YYYY HH24:MI') end_date FROM TT)) 
        CONNECT BY LEVEL <= end_date - start_date + 1) WHERE dt IN ('friday','saturday')) as worked_hours
FROM TT

【问题讨论】：

标签： oracle

【解决方案1】：

您可以尝试使用分层查询

WITH t 
     AS (SELECT To_date ('8/20/2014 13:52', 'MM/DD/YYYY HH24:MI') start_date, 
                To_date ('8/28/2014 13:52', 'MM/DD/YYYY HH24:MI') end_date 
         FROM   dual) 
SELECT Count(*) 
FROM   (SELECT To_char(start_date + ( LEVEL - 1 ), 'fmday') dt 
        FROM   t 
        CONNECT BY LEVEL <= end_date - start_date + 1) 
WHERE  dt IN ( 'friday', 'saturday' );


RESULT
------
2

* 通过扩大范围列出日期。 * TO_CHAR 函数用于获取工作日 * 计算星期五或星期六的所有内容

如果你想计算日期，那么你可以试试

SELECT To_char(dat, 'DY'), 
       Count(*) 
FROM   (SELECT To_date ('8/20/2014 13:52', 'MM/DD/YYYY HH24:MI') 
               + num dat 
        FROM   (SELECT LEVEL - 1 num 
                FROM   dual 
                CONNECT BY LEVEL <= Abs(To_date ('8/20/2014 13:52', 
                                        'MM/DD/YYYY HH24:MI') - 
                                                             To_date ( 
                                        '8/28/2014 13:52' 
                                                             , 
                                        'MM/DD/YYYY HH24:MI')) - 1 
               )) 
WHERE  To_char(dat, 'DY') IN ( 'FRI', 'SAT' ) 
GROUP  BY To_char(dat, 'DY');


RESULTS

TO_CHAR(DAT,'DY')   COUNT(*)
-----------------   --------
FRI                   1
SAT                   1

【讨论】：

@realsprituals 我修改了你的第一个查询并运行它.. 它给出了缺少选择错误.. 你能帮忙.. 我在我的问题的更新部分更新我的查询
你不能像这样使用公用表表达式。

【解决方案2】：

您可以像这样计算星期六和星期日的数量：

with t(d) as (
  select sysdate + level from dual connect by rownum < 10
)
select count(case when trim(to_char(d, 'DAY')) in ('SATURDAY', 'SUNDAY') then 1 end) cnt from t

CNT
---
  2

如果您没有日期范围，那么：

with t(a, b) as (
  select sysdate a, sysdate + 10 b from dual connect by rownum < 10
), t2(d) as (
  select a + level - 1 from t connect by rownum <= b - a
)
select count(case when trim(to_char(d, 'DAY')) in ('SATURDAY', 'SUNDAY') then 1 end) cnt from t2

CNT
---
  2

【讨论】：