COUNT 组的总数 by mysql

Question

这个 mysql 查询为我提供了按天和小时分组的产品销售数量（total 和 total_staff）。我想要每个产品的 total 和 total_staff 的总和（不按任何东西分组，按 id 分组）。我可以在同一个查询中执行此操作吗？

SELECT p.name, p.color, DATE(date_create) as jour,HOUR(date_create) AS h,
SUM(CASE WHEN s.staff=0 THEN 1 ELSE 0 END) as total,
SUM(CASE WHEN s.staff=1 THEN 1 ELSE 0 END) as total_staff
FROM manifsSubCategories msc
LEFT JOIN products_subCategories psc ON msc.id=psc.manifSubCategory_id
LEFT JOIN sales s ON psc.product_id=s.product_id
LEFT JOIN products p ON psc.product_id=p.id
LEFT JOIN manifsCategories ON manifCategory_id=manifsCategories.id
WHERE manifCategory_id=1 AND s.category_id=1 GROUP BY jour,h ORDER BY p.id DESC 

Answer 1

只需省略其他列：

SELECT p.name,
    SUM(CASE WHEN s.staff=0 THEN 1 ELSE 0 END) as total,
    SUM(CASE WHEN s.staff=1 THEN 1 ELSE 0 END) as total_staff
FROM manifsSubCategories msc
LEFT JOIN products_subCategories psc ON msc.id=psc.manifSubCategory_id
LEFT JOIN sales s ON psc.product_id=s.product_id 
LEFT JOIN products p ON psc.product_id=p.id
LEFT JOIN manifsCategories ON manifCategory_id=manifsCategories.id
WHERE manifCategory_id=1 AND s.category_id=1
GROUP BY p.name
ORDER BY p.id DESC

顺便说一句 - 您的 WHERE 子句是错误的。您正在按LEFT JOIN 的表进行过滤，这将由于NULL 比较而将您的联接变成inner join。
左联接右表上的条件只能放在ON 内子句。