按年份将游戏分组到季节

Question

我正在构建一个棒球统计应用程序。我无法将游戏分成季节。

一场比赛有_许多击球、投球和防守。游戏也有一个played_date 字段，我可以从中获取年份。

基本上我想做的就是能够将游戏分成季节，并在那个季节中添加列。

例如，能够做到：

<% @player.each do |player| %>
    <% player.battings.seasons.each do |battingseason| %>
        <%= battingseason.total("homeruns") %>
    <% end %>
<% end %>

所以 "battingseason.total("homeruns")" 将总结特定球员在该赛季中击出的总本垒打数。

我可以通过这个获得玩过哪些游戏的年份：

@game_seasons = @games.group_by { |g| g.played_date.beginning_of_year }

...但我不确定它有多大帮助。

从那里开始，我还需要能够将季节分为秋季和春季。例如，我目前拥有的：

def season
    if self.game.played_date.month >= 9 && self.game.played_date.month <= 12
        season = "fall"
    else
        season = "spring"
    end
end

所以我的问题是我只是不确定将所有这些逻辑放在哪里，在控制器中，在模型中？以及具体如何输出，谢谢！

Answer 1

我会创建一个Season 模型。季节模型有一栏，season。我会这样设置模型：

class Season < ActiveRecord::Base
  has_many :games
  has_many :battings, through: :games
  has_many :pitchings, through: :games
  has_many :fieldings, through: :games
end

class Game < ActiveRecord::Base
  belongs_to :season
end

您需要将season_id 添加到games 表中，并且可以在game 模型中添加before_validate 方法：

before_validate :find_or_create_season

private

def find_or_create_season
  if self.played_date.month >= 9 && self.played_date.month <= 12
    season = "fall"
  else
    season = "spring"
  end
  season_name = season + ' ' + self.played_date.year.to_s
  game_season = Season.find_or_create_by_season(season_name)
  self.season_id = game_season.id
end

我不确定您希望您的视图看起来如何，但这是一种可能性。这将按赛季为您提供一名球员的本垒打总结：

在您的控制器中：

def show
  @player = Player.find(params[:id])

  #not sure how you define if a batting was a homerun. I assumed that you have a boolean for that
  @homeruns_by_season = @player.battings.where('homerun = ?', true).group(:season).count
  #this will return a hash with season as a key and the count as the value

end

在你看来

<% @homeruns_by_season.each do |season, homeruns| %>
  <td><%= season.season %></td>
  <td><%= homeruns %></td>
<% end %>