返回下一个季节和年份

Question

对于开始的特定季节和年份，我必须得到下一个开始的季节和年份，例如对于 2021 年夏季，我应该获得 2021 年秋季，对于 2021 年冬季，我应该获得 2022 年春季。

“Seasons”表有“Order”列，表示一年中的季节顺序，如下所示：

SeasonID	Order	Name
1	1	Spring
2	2	Summer
3	3	Autumn
4	4	Winter

备注：“订单”列可能看起来多余，但这实际上是我遇到的问题的简化/改编版本，其中“订单”列是必要的。

我有一个以@Year 和@SeasonID 作为输入参数的存储过程。我必须在@FollowingSeasonID 和@FollowingYear 参数中获取以下季节/年份，稍后我将在存储过程中使用它们。我不确定我是否使用了最好的技术：

(...)

    DECLARE @FollowingSeasonID int;
    DECLARE @FollowingYear int;
    if object_id('tempdb..#Years') is not null drop table #Years
    CREATE TABLE #Years ([Year] int)
    INSERT INTO #Years ([Year]) VALUES (@Year), (@Year + 1)

    SELECT @FollowingSeasonID = FollowingSeasonID, @FollowingYear = FollowingYear
    FROM
        (SELECT SeasonID, 
                [Year], 
                LEAD(SeasonID) OVER (ORDER BY [Year], Order) AS FollowingSeasonID,
                LEAD([Year]) OVER (ORDER BY [Year], Order) AS FollowingYear
        FROM Seasons
        CROSS JOIN #Years) t
    WHERE SeasonID = @SeasonID AND [Year] = @Year

(...)

有没有更好的方法来做到这一点？是否可以在一个查询中实现？

我需要在多个存储过程/视图/...中使用这些值，所以如果是函数，我想提取那部分代码。标量值函数不能返回两个值，所以我必须创建一个表值函数（并且我必须使用表变量而不是临时表 #Years）。但是，有没有更好的方法来做到这一点，而不是让一个总是只返回一行的表值函数？

Answer 1

您可以将此代码包装在 UDF 中，您应该能够获得 seasonId, year

DECLARE @season table(SeasonId int, SeasonOrder int, Name varchar(10))
INSERT INTo @season values
(1,    1    ,'Spring')
,(2,    2   ,'Summer')
,(3,    3   ,'Autumn')
,(4,    4   ,'Winter');

DECLARE @FollowingSeasonID int;
DECLARE @FollowingYear int;
DECLARE @year int = 2021, @SeasonId int = 2;

;WITH CTE_YearSeason AS
(
SELECT y,s.* FROM @season as s
CROSS APPLY
(VALUES (@year), (@year+1)
) as t(y)
), cte_ranking as
(
SELECT *, row_number() over (order by y,SeasonOrder) as rnk 
FROM CTE_YearSeason)
SELECT SeasonId, Y as year 
FROM  cte_ranking as c
where c.rnk = (SELECT c1.rnk 
from cte_ranking as c1
where c1.SeasonId = @SeasonId and c1.y = @year) +1

SeasonId	year
3	2021

Answer 2

除非我误解了，给定一个 seasonId，您只需要以下 Id 并将其重置为 1 并在必要时增加年份？

declare @seasonid int=1, @Year int=2021

select  FollowingSeasonID, @Year + yr FollowingYear
from (
    select *,
        IsNull(Lead(SeasonId) over(order by [order]),1) FollowingSeasonID,
        case when Lead(SeasonId) over(order by [order]) is null then 1 else 0 end yr
    from seasons
)s
where SeasonId=@SeasonId 

如果您不想使用 TVF，您可以将其用作视图/cte，加入 currentId 并返回 followingId 和 yr 值以添加到您的当前年份。