Mysql每年按月获取行数答案

【问题标题】：Mysql getting rows by each month in each yearMysql每年按月获取行数
【发布时间】：2017-04-19 12:27:50
【问题描述】：

我试图找出每年每个月的总成本。

我有下表“日志”

date               |    cost
---------------------------------
Wed, 01 Aug 2016   |    45
Tue, 15 Aug 2016   |    52
Mon, 31 Aug 2016   |    23
Thu, 05 Sep 2016   |    9
Sat, 10 Sep 2016   |    33
Mon, 12 Feb 2017   |    8
Tue, 31 Feb 2017   |    0
Wed, 31 Mar 2017   |    100
Fri, 31 Mar 2017   |    35
Thu, 31 Mar 2017   |    45

这就是我想要达到的目标，

2017

二月 8+0

三月 100+35+45

2016

8 月 45+52+23

九月 9+33

目前我正在这样做，

$sqly = "SELECT DISTINCT RIGHT(date,4) as year FROM logs ORDER BY id DESC;";
$resy = mysql_query($sqly);
while($rowy = mysql_fetch_array($resy))
{
   echo $rowy['year'];
}

结果：

2017

2016

我不知道如何进一步获取每年的月份并将每个月的总数相加。

【问题讨论】：

编辑查询并解析月份
见meta.stackoverflow.com/questions/333952/…

标签： php mysql

【解决方案1】：

这个查询应该可以工作：

SELECT YEAR(STR_TO_DATE(date, '%W, %d %M %Y')) AS year,
       MONTH(STR_TO_DATE(date, '%W, %d %M %Y')) AS month, 
       SUM(cost) 
FROM logs 
GROUP BY year, month;

【讨论】：

【解决方案2】：

试试这个查询。

SELECT YEAR(date) AS year, MONTH(date) AS month, COUNT(DISTINCT id) FROM logs GROUP BY year, month

【讨论】：

我将年份和月份设为 NULL 以及条目数。

【解决方案3】：

You can use below code to find your answer, Hope this will help you

<?php

$sqly = "SELECT DISTINCT RIGHT(date,4) as year FROM logs ORDER BY id DESC;";
$resy = mysql_query($sqly);
while($rowy = mysql_fetch_array($resy))
{
   echo $rowy['year'];

   $sqly2 = "select SUBSTRING(date, 9, 3) as month_name, Group_concat(cost,' + ') as total_cost from logs where RIGHT(date,4) = '".$rowy['year']."' GROUP BY SUBSTRING(date, 9, 3)";
    $resy2 = mysql_query($sqly2);

    while($rowy2 = mysql_fetch_array($resy2))
{
   echo $rowy2['month_name'] ." ".$rowy2['total_cost'] ;

}
}

【讨论】：

感谢您的回答。