解析 XML 并将其转换为数据框的最佳方法

Question

我有以下 XML（它是一个示例）：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<HDR_DONNEES xmlns="http://ERABLE_HDR.com/ns1">
    <Dates>
        <Date valeur="14032019">
            <Depart ACR_DepartHTA="BDX" ACR_PosteSource="BDX" GdoDepart="V.LOTC0018" Nom_DepartHTA="BOURLANG" PS_DepartHTA="V.LOT" NomPosteSource="VILLELOT">
                <M H="1150" UTM="20850" ITM="94" IFg="0" UNB="1" INB="1"/>
            </Depart>
            <Depart ACR_DepartHTA="BDX" ACR_PosteSource="BDX" GdoDepart="V.LOTC0005" Nom_DepartHTA="MARCHE G" PS_DepartHTA="V.LOT" NomPosteSource="VILLELOT">
                <M H="1150" UTM="20850" ITM="41" IFg="0" UNB="1" INB="1"/>
            </Depart>
            <Depart ACR_DepartHTA="NTS" ACR_PosteSource="NTS" GdoDepart="PALLUC2703" Nom_DepartHTA="FROIDFON" PS_DepartHTA="PALLU" NomPosteSource="PALLUAU">
                <M H="1140" UTM="0" ITM="0" IFg="100" UNB="0" INB="1"/>
            </Depart>
        </Date>
    </Dates>
</HDR_DONNEES>

我怎样才能将这个 XML 解析成一个数据框以便拥有这种结构？

|-- acrDeparthta: 字符串 (nullable = true)

|-- acrPostesource: 字符串 (nullable = true)

|-- gdodepart: 字符串 (nullable = true)

|-- nomDeparthta: string (nullable = true)

|-- psDeparthta: 字符串 (nullable = true)

|-- nompostesource: string (nullable = true)

|-- 创建日期：字符串（可为空=真）

|-- m: 数组（可为空=真）

| |-- 元素：结构（containsNull = true）

| | |-- h: 字符串（可为空=真）

| | |-- utm: string (nullable = true)

| | |-- ufg: 字符串 (nullable = true)

| | |-- itm: string (nullable = true)

| | |-- ifg: string (nullable = true)

| | |-- unb: string (nullable = true)

| | |-- inb: 字符串 (nullable = true)

“M”以下的任何属性都是“M”数组的一部分。

任何帮助将不胜感激，谢谢！

编辑：

我试过这个：

import xml.etree.ElementTree as ET
tree = ET.parse('testtest.xml')
root = tree.getroot()

for child in root:
    print child.tag, child.attrib

但我得到的只是：{http://ERABLE_HDR.com/ns1}日期{}

如果我在同一个循环中更深入地重复使用它

for child in child:
    print child.tag, child.attrib

我明白了：{http://ERABLE_HDR.com/ns1}日期 {'valeur': '14032019'}

它会一直持续下去..

Answer 1

我建议将BeautifulSoup 与lxml 阅读器一起使用（如果我正确理解了您的要求）：

from bs4 import BeautifulSoup
import pandas as pd

xml=b"""\
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<HDR_DONNEES xmlns="http://ERABLE_HDR.com/ns1">
    <Dates>
        <Date valeur="14032019">
            <Depart ACR_DepartHTA="BDX" ACR_PosteSource="BDX" GdoDepart="V.LOTC0018" Nom_DepartHTA="BOURLANG" PS_DepartHTA="V.LOT" NomPosteSource="VILLELOT">
                <M H="1150" UTM="20850" ITM="94" IFg="0" UNB="1" INB="1"/>
            </Depart>
            <Depart ACR_DepartHTA="BDX" ACR_PosteSource="BDX" GdoDepart="V.LOTC0005" Nom_DepartHTA="MARCHE G" PS_DepartHTA="V.LOT" NomPosteSource="VILLELOT">
                <M H="1150" UTM="20850" ITM="41" IFg="0" UNB="1" INB="1"/>
            </Depart>
            <Depart ACR_DepartHTA="NTS" ACR_PosteSource="NTS" GdoDepart="PALLUC2703" Nom_DepartHTA="FROIDFON" PS_DepartHTA="PALLU" NomPosteSource="PALLUAU">
                <M H="1140" UTM="0" ITM="0" IFg="100" UNB="0" INB="1"/>
            </Depart>
        </Date>
    </Dates>
</HDR_DONNEES>"""


soup = BeautifulSoup(xml,features="lxml")

data={}
for i,depart in enumerate(soup.find_all('depart')):
    data[i]=depart.attrs
    for m in depart.findChildren():
        data[i]['m']=list(m.attrs.values())

df=pd.DataFrame.from_dict(data, orient='index')
print(df)

返回：

  acr_departhta acr_postesource   gdodepart nom_departhta ps_departhta nompostesource                           m
0           BDX             BDX  V.LOTC0018      BOURLANG        V.LOT       VILLELOT  [1150, 20850, 94, 0, 1, 1]
1           BDX             BDX  V.LOTC0005      MARCHE G        V.LOT       VILLELOT  [1150, 20850, 41, 0, 1, 1]
2           NTS             NTS  PALLUC2703      FROIDFON        PALLU        PALLUAU     [1140, 0, 0, 100, 0, 1]