是否可以在一维数组中获取所有 XML 数据？

Question

例子：

<school>
  <students>
    <student idNumber="123" enrollmentNo="E101">
      <name>
        <firstname>Jack</firstname>
        <lastname>Harmor</lastname>
        <standard>7th</standard>
      </name>
    </student>
    <student idNumber="243">
      <name>
        <firstname>Cris</firstname>
        <lastname>Warner</lastname>
        <standard>5th</standard>
      </name>
    </student>
    <student idNumber="345">
      <name>
        <firstname>Rick</firstname>
        <lastname>Corner</lastname>
        <standard>6th</standard>
      </name>
    </student>
  </students>
  <fees type="teaching">
    <fifth>100</fifth>
    <sixth>110</sixth>
    <seventh>120</seventh>
  </fees>
</school>

我想创建一个如下所示的数组

array(
  [students_student_name_firstname0]=>Jack,
  [students_student_name_lastname0]=>Harmor,
  [students_student_name_standard0]=>7th,
  [students_student_name_firstname1]=>Cris,
  [students_student_name_lastname1]=>Warner,
  [students_student_name_standard1]=>5th,
  [students_student_name_firstname2]=>Rick,
  [students_student_name_lastname2]=>Corner,
  [students_student_name_standard2]=>6th,
  [students_fifth0]=>100,
  [students_sixth0]=>110,
  [students_seventh0]=>120,
  [attributes]=>array(
    [student0]=>array(
      [idNumber]=>123,
      [enrollmentNo]=>E101
    ),
    [student1]=>array(
      [idNumber]=>243
    ),
    [student2]=>array(
      [idNumber]=>345
    )
  )
);

上面是这种 XML 可能被发送以获取数据的示例，但问题是 XML 的任何级别可能是级别 1、2、3、..、N，所以我怎样才能获取所有数据如上所述的单/二维数组（这意味着数组的有限级别）以及动态存储其键名称和值以及属性名称及其特定标签的值的最简单方法是什么？或者，如果您有更好的方法来做到这一点，那么您也可以分享。我对此一无所知，所以请帮助我。 提前致谢。

Answer 1

对于直接转换为数组，您可以按照自己的意愿在循环中处理它：

$array = json_decode(json_encode(simplexml_load_string($xml)), true);

但是，如果你想尽可能地变平，那么你可以做一些额外的事情，比如：

$xml = '
<school>
  <students>
    <student idNumber="123" enrollmentNo="E101">
      <name>
        <firstname>Jack</firstname>
        <lastname>Harmor</lastname>
        <standard>7th</standard>
      </name>
    </student>
    <student idNumber="243">
      <name>
        <firstname>Cris</firstname>
        <lastname>Warner</lastname>
        <standard>5th</standard>
      </name>
    </student>
    <student idNumber="345">
      <name>
        <firstname>Rick</firstname>
        <lastname>Corner</lastname>
        <standard>6th</standard>
      </name>
    </student>
  </students>
  <fees type="teaching">
    <fifth>100</fifth>
    <sixth>110</sixth>
    <seventh>120</seventh>
  </fees>
</school>
';

$array = json_decode(json_encode(simplexml_load_string($xml)), true);

$result = [];
foreach ($array['students']['student'] as $element) {
    $data = [];

    foreach ($element as $elements) {
        foreach ($elements as $k => $v) {
            $data[$k] = $v;
        }
    }

    $result[] = $data;
}

$fees = [];
foreach ($array['fees'] as $k => $v) {
    if ($k == '@attributes') {
        foreach ($v as $attr => $val) {
            $fees[$attr] = $val;
        }
    } else {
        $fees[$k] = $v;
    }
}

$result['fees'] = $fees;

echo '<pre>';
print_r($result);

结果：

Array
(
    [0] => Array
        (
            [idNumber] => 123
            [enrollmentNo] => E101
            [firstname] => Jack
            [lastname] => Harmor
            [standard] => 7th
        )

    [1] => Array
        (
            [idNumber] => 243
            [firstname] => Cris
            [lastname] => Warner
            [standard] => 5th
        )

    [2] => Array
        (
            [idNumber] => 345
            [firstname] => Rick
            [lastname] => Corner
            [standard] => 6th
        )

    [fees] => Array
        (
            [type] => teaching
            [fifth] => 100
            [sixth] => 110
            [seventh] => 120
        )

)

Answer 2

为了能够获取具有 in 值的所有文本节点（即排除任何文档中的正常空白）和所有属性，您可以使用以下代码。请注意，这不会为您提供与您提供的相同格式，但该格式应该允许您在之后想出一些东西..

$xml = new DOMDocument();
$xml->preserveWhiteSpace = false;
$xml->load($file);
$xp = new DOMXPath($xml);
$entries = $xp->query("//node()[not(node())][string-length(normalize-space(.) ) > 1]");
foreach ( $entries as $data )   {
    echo $data->getNodePath()."=".$data->nodeValue.PHP_EOL;
}

echo "Attributes".PHP_EOL;
$attributes = $xp->query("//@*");
foreach ( $attributes as $data )   {
    echo $data->getNodePath()."=".$data->nodeValue.PHP_EOL;
}

给...

/school/students/student[1]/name/firstname/text()=Jack
/school/students/student[1]/name/lastname/text()=Harmor
/school/students/student[1]/name/standard/text()=7th
/school/students/student[2]/name/firstname/text()=Cris
/school/students/student[2]/name/lastname/text()=Warner
/school/students/student[2]/name/standard/text()=5th
/school/students/student[3]/name/firstname/text()=Rick
/school/students/student[3]/name/lastname/text()=Corner
/school/students/student[3]/name/standard/text()=6th
/school/fees/fifth/text()=100
/school/fees/sixth/text()=110
/school/fees/seventh/text()=120
Attributes
/school/students/student[1]/@idNumber=123
/school/students/student[1]/@enrollmentNo=E101
/school/students/student[2]/@idNumber=243
/school/students/student[3]/@idNumber=345
/school/fees/@type=teaching

您可能希望删除名称的某些部分（即text()）等。

虽然坚持按原样处理 XML 会更好。