【发布时间】:2014-10-17 13:30:22
【问题描述】:
所以我想用 Java GregorianCalendar 做一些事情,这似乎比它应该做的要困难得多。我想从月份和日期中获取星期几。但它不会那样做。我知道人们经常得到错误的答案,因为他们不知道月份从 0 开始编号,而 DAY_OF_WEEK 从 1 开始编号(例如 here 和 here)。但这不是我的问题。我的问题是 DAY_OF_WEEK 总是返回 7,无论我将日期设置为什么。当我将 GregorianCalendar 转换为字符串时,DAY_OF_WEEK 显示为?,即使我设置了年、月和日。
发生这种情况的代码:
GregorianCalendar theDate;
public ObservableDate(int year, int month, int dayOfMonth, int hourOfDay, int minute, int second)
{
theDate = new GregorianCalendar(year, month, dayOfMonth, hourOfDay, minute, second);
theDate.setFirstDayOfWeek(GregorianCalendar.SUNDAY);
System.out.println("DAY_OF_WEEK = "+theDate.DAY_OF_WEEK);
System.out.println(theDate.toString());
}
调用它的代码:
ObservableDate theDate = new ObservableDate(2001, 3, 24, 9, 00, 00);
输出:
DAY_OF_WEEK = 7
java.util.GregorianCalendar[time=?,areFieldsSet=false,areAllFieldsSet=false,lenient=true,zone=sun.util.calendar.ZoneInfo[id="America/New_York",offset=-18000000,dstSavings=3600000,useDaylight=true,transitions=235,lastRule=java.util.SimpleTimeZone[id=America/New_York,offset=-18000000,dstSavings=3600000,useDaylight=true,startYear=0,startMode=3,startMonth=2,startDay=8,startDayOfWeek=1,startTime=7200000,startTimeMode=0,endMode=3,endMonth=10,endDay=1,endDayOfWeek=1,endTime=7200000,endTimeMode=0]],firstDayOfWeek=1,minimalDaysInFirstWeek=1,ERA=?,YEAR=2001,MONTH=3,WEEK_OF_YEAR=?,WEEK_OF_MONTH=?,DAY_OF_MONTH=24,DAY_OF_YEAR=?,DAY_OF_WEEK=?,DAY_OF_WEEK_IN_MONTH=?,AM_PM=0,HOUR=9,HOUR_OF_DAY=9,MINUTE=0,SECOND=0,MILLISECOND=?,ZONE_OFFSET=?,DST_OFFSET=?]
知道为什么会这样吗?
【问题讨论】:
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仅供参考,麻烦的旧日期时间类,例如
java.util.GregorianCalendar现在是 legacy,被 Java 8 和 Java 9 中内置的 java.time 类所取代。请参阅 Tutorial by Oracle。跨度>
标签: java calendar dayofweek gregorian-calendar