【发布时间】:2015-05-07 03:32:49
【问题描述】:
#include <iostream>
#include <ctime>
int *initialize(int []);
bool check(int random_num, int []);
int *draw(int []);
int *printout(int user_input, int []);
int entry(int user_input);
using namespace::std;
int wins[10]; // sets global array
int random_num; //stores global var for random numbers
int user_input; //stores global var for user entered number
int main(){
int nothing; // used to pause program
initialize(wins);
draw(wins);
entry(user_input);
check(user_input, wins);
printout(user_input, ::wins);
cin >> nothing; // used to pause program
}
//Initializes the array wins[] with the value -1
int *initialize(int wins[]){
for (int i = 0; i < 10; ++i)
::wins[i] = {-1};
return ::wins;
}
// draws 10 random numbers and fills the array with them
int *draw(int wins[]){
for (int i = 0; i < 10; i++){
srand(time(NULL));
::random_num = rand() % 100;
::wins[i] = ::random_num;
}
return ::wins;
}
//Allows the user to enter a number and stores the number entered
int entry(int user_input){
cout << "Pick a number between (0 and 99): ";
cin >> ::user_input;
return ::user_input;
}
//Checks to see if the number guessed is a winning number
bool check(int user_input, int wins[]){
for (int i = 0; i <= 10; i++){ // starts evaluating from win[0]
if (::user_input == ::wins[i]){ // checks for matching numbers to decide if winner
cout << "Number selected: " << user_input << endl << "You win!";
return true;
}
if (::user_input != ::wins[i]){ // checks for mis-matching numbers to decide if loser
cout << "Number selected: " << user_input << endl << "You lose!";
return false;
}
}
}
// Sends the selected lottery numbers to the user in a spaced format
int *printout(int user_input, int wins[]){
cout << endl << "Lottery numbers: ";
for (int i = 10; i >= 0; i--)
cout << ::wins[i] << " ";
return ::wins;
}
我通过 main() 跟踪程序,wins[] 填充了所有相同的值,但是当我隔离 draw() 并遵循循环时,数组正确填充了随机数......我不知道为什么?!帮助
【问题讨论】:
-
为什么是全局变量?使用您已经设置的参数。
-
为什么要使用全局变量?您将参数传递给函数,以及一些仅在单个函数中使用的全局变量,这意味着您应该使用 local 变量。
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这项作业有一些我最初试图解决的限制。我现在要让它与局部变量一起工作。谢谢!