【发布时间】:2016-03-13 04:58:12
【问题描述】:
我有一个问题,如何使用分数坐标递归绘制矩形?我一直试图让正方形/矩形每次变小 10%,直到它占据整个画布(这意味着它不能超出板的宽度和高度,或者它只是变成 0 意味着它不会绘制任何东西,否则它太小了,你看不到最后的正方形)。或者,也许有另一种方法可以让我以递归方式绘制正方形,并不断减少一定的百分比?
到目前为止,我有这个,但我似乎想不出谁让它继续递归,直到它不能再这样做。
import tkinter
class draw_squares:
def __init__(self, squares: [(float, float, float, float)]):
self.squares = squares
self.root_window = tkinter.Tk()
self.canvas = tkinter.Canvas(master = self.root_window,
width = 500, height = 500,
background = 'blue')
self.canvas.grid(row=0, column = 0, padx=0, pady = 0,
sticky = tkinter.E + tkinter.W + tkinter.S + tkinter.N)
self.canvas.bind('<Configure>', self._resized)
self.root_window.rowconfigure(0, weight = 1)
self.root_window.columnconfigure(0, weight = 1)
def start(self):
self.root_window.mainloop()
def _resized(self, event: tkinter.Event):
self.draw_squares_recursively()
def draw_squares_recursively(self):
self.canvas.delete(tkinter.ALL)
for x, y, x2, y2 in self.squares:
if x != 0.5 and y != 0.5 and x2 != 0.5 and y2 != 0.5:
self._draw_square(self._draw_square(x-.1,y-.1,x2+.1,y2+.1))
def _draw_square(self, x: float, y:float, x2:float, y2:float):
width = self.canvas.winfo_width()
height = self.canvas.winfo_height()
self.canvas.create_rectangle(
x * width, y * height,
x2 * width, y2 *height, outline = 'grey')
if __name__ == '__main__':
squares = [(0.9, 0.9, 0.1, 0.1), (0.8,0.8,0.2,0.2), (0.7,0.7,0.3,0.3),
(0.6,0.6,0.4,0.4), (0.5,0.5,0.5,0.5)]
app = draw_squares(squares)
app.start()
非常感谢您的帮助!
【问题讨论】:
标签: python class recursion tkinter