【发布时间】:2017-10-30 15:20:27
【问题描述】:
我正在构建一个简单的天气应用程序,没什么复杂的,我只需要根据用户位置从 Open Weather Map 中获取 JSON。这是从 WOM http://api.openweathermap.org/data/2.5/weather?lat=52.516221&lon=13.408363&appid=e72ca729af228beabd5d20e3b7749713 获取 JSON 的正确 URL 结构
但是,这是我的快速代码/Alamofire 给我的http://api.openweathermap.org/data/2.5/weather?appid=e72ca729af228beabd5d20e3b7749713&lat=52.516221&long=13.408363
所以它将apiid=*** 放在url 的开头而不是结尾。
这是我的代码。
let WEATHER_URL = "http://api.openweathermap.org/data/2.5/weather"
let APP_ID = "e72ca729af228beabd5d20e3b7749713"
func getWeatherData(url: String, parameters : [String : String]) {
Alamofire.request(url, method: .get, parameters: parameters).responseJSON {
response in
if response.result.isSuccess {
print ("Everything is fine")
print ( Alamofire.request(url, method: .get, parameters: parameters))
let weatherJSON : JSON = JSON(response.result.value!)
print (weatherJSON)
}
else {
print ("Error \(String(describing: response.result.error))")
self.cityLabel.text = "Connection issues"
}
}
}
func locationManager(_ manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {
let location = locations[locations.count - 1]
if location.horizontalAccuracy > 0 {
locationManager.stopUpdatingLocation()
let latitude = "52.516221"
let longitude = "13.408363"
let params : [String : String] = ["lat" : latitude, "long" : longitude, "appid" : APP_ID]
getWeatherData(url : WEATHER_URL, parameters : params)
}
}
【问题讨论】:
标签: swift alamofire openweathermap