【发布时间】:2015-08-14 08:06:16
【问题描述】:
在我的程序中,我想从一行中提取一个数字(表示以秒为单位的停止时间),然后我从下一行中提取另一个数字(表示以秒为单位的开始时间),然后将结果写入结果文件。
我有以下代码:
# include <iostream>
# include <fstream>
# include <string>
# include <streambuf>
using namespace std;
int main ()
{
ifstream f;
ofstream g;
f.open("Processes.txt");
g.open("Results.txt");
long last_el,top_nr=0,stop_nr=0,start_nr=0,stop_time_count=1,start_time_count=1,inter_count=0,global_count,final_result_count=1;
long pow_start_nr=7,pow_stop_nr=7,stop_time[1000],start_time[1000],final_result[1000];
string text_el;
stringstream strStream;
strStream << f.rdbuf();
string str = strStream.str();
last_el=text_el.size();
// while(text.el)
// {
for(global_count=0;global_count<last_el;global_count++)
{
if(text_el[global_count]=='*')
{
inter_count=global_count+1;
for(global_count=inter_count;global_count<=inter_count+7;global_count++)
{
start_nr=start_nr+(10^pow_start_nr)*text_el[global_count];
pow_start_nr--;
}
start_time[start_time_count]=start_nr;
start_time_count++;
global_count=inter_count+8;
}
}
for(global_count=0;global_count<last_el;global_count++)
{
if(text_el[global_count]=='#')
{
inter_count=global_count+1;
for(global_count=inter_count;global_count<=inter_count+7;global_count++)
{
stop_nr=stop_nr+(10^pow_stop_nr)*text_el[global_count];
pow_stop_nr--;
}
stop_time[stop_time_count]=stop_nr;
stop_time_count++;
global_count=inter_count+8;
}
}
// }
for(final_result_count=1;final_result_count<2;final_result_count++)
{
final_result[final_result_count]=stop_time[stop_time_count]-start_time[start_time_count];
stop_time_count++;
start_time_count++;
g<<"The time for process number"<<" "<< final_result_count <<" "<<"is"<<" "<< final_result[final_result_count] <<endl<<endl;
}
f.close();
g.close();
}
在我的退出文件中,它只写了 0。
我不知道为什么会这样。我认为从文件中读取的文本有问题。 在那里,带有“ a ”向量。我是 C++ 的菜鸟。
乐:
# include <iostream>
# include <fstream>
# include <string>
# include <sstream>
# include <streambuf>
using namespace std;
int main ()
{
ifstream f;
ofstream g;
f.open("Processes.txt");
g.open("Results.txt");
long startTime[1000],endTime[1000];
string nextLine;
int lineNum = 1;
while (getline(f, nextLine))
{
getline(f, nextLine);
startTime[lineNum] = stoi(nextLine.substr(14,8));
g<<startTime[lineNum]<<"xxxx";
endTime[lineNum+1] = stoi(nextLine.substr(27,8));
g<<endTime[lineNum]<<"xxxx";
getline(f, nextLine);
getline(f, nextLine);
getline(f, nextLine);
lineNum=lineNum+3;
}
f.close();
g.close();
}
输入文件:
------------------------------------------------------------------------------
started at: *00000005 Number: 1
completed at: #00000065 Number: 1
------------------------------------------------------------------------------
------------------------------------------------------------------------------
started at: *00000000 Number: 2
completed at: #00000100 Number: 2
------------------------------------------------------------------------------
------------------------------------------------------------------------------
started at: *09999999 Number: 3
completed at: #10000000 Number: 3
【问题讨论】:
-
变量名允许超过一个字符。例如,如果您将
d[1000]更改为final_results[1000],程序会更容易阅读。 -
好的,我会的,谢谢!
-
伙计,请按照 C++ 编码指南编写代码。这是一个好习惯。
-
@Alexander 没有“C++ 编码指南”,但肯定有常识。
-
当您的输入以
------开头时,您希望f >> n做什么?