php电子邮件发送不起作用[重复]

Question

这是我发送电子邮件的 php 代码。我收到了“消息已发送，您可以发送另一个消息”的消息，但未发送电子邮件。

     <h4>Please fill out the following form and we will be in touch with you soon.</h4>
<form action="mytest.php" method="post" id="contactform">
  <ol>
    <li>
      <label for="name">Your Name <span class="red">*</span></label>
      <input id="name" name="name" class="text" />
    </li>
    <li>
      <label for="email">Your email <span class="red">*</span></label>
      <input id="email" name="email" class="text" />
    </li>
    <li>
      <label for="subject">Subject</label>
      <input id="subject" name="subject" class="text" />
    </li>
    <li>
      <label for="message">Message <span class="red">*</span></label>
      <textarea id="message" name="message" rows="6" cols="50"></textarea>
    </li>
    <li class="buttons">
      <input type="image" name="imageField" id="imageField" src="images/send.gif" class="send" />
      <div class="clr"></div>
    </li>
  </ol>
</form> 


<?php

if(!$_POST) exit;

$email = $_POST['email'];

$errors=0;

if($errors==1) echo $error;
else{
    $email_from = $_POST['email'];
$email_from = "from@gmail.com";
$headers = "From: " . strip_tags( $_POST['name'] ) . "\r\n";

$mail_to_send_to = "to@gmail.com";
$your_feedbackmail = "from@gmail.com";
$sendflag = 'send';                       
if ( $sendflag == "send" )
        {
                $email = $_REQUEST['email'] ;
                $message = $_REQUEST['message'] ;
                $headers = "From: $your_feedbackmail" . "\r\n" . "Reply-To: $email" . "\r\n" ;
                $a = mail( $mail_to_send_to, "Feedback Form Results", $message, $headers );
                if ($a)
                {
                     print("Message was sent, you can send another one");
                } else {
                     print("Message wasn't sent, please check that you have changed emails in the bottom");
                }
        }
}
?>

我正在使用 Cpanel 来托管我的网站。有什么特殊的配置可以做到这一点吗？我是 php 新手。请帮帮我。

Answer 1

邮件功能不提供身份验证功能。您必须使用 Mail Pear 包中的 Mail 类。示例见这里：

example

Answer 2

我假设您使用的是共享主机，因为您使用的是 Cpanel，一些共享主机解决方案不能很好地与 php 的 mail() 函数配合使用，我发现使用 phpmailer https://github.com/PHPMailer/PHPMailer 效果更好并提供更多功能

使用 phpmailer ： 从链接下载，将文件放在您的网络应用程序可访问的文件夹中。

代码：

$email_from = $_POST['email'];
$email_from = "from@gmail.com";  // this overwrites the $_POST['email'] value, check this
$email_from_name = "Nishanthi";
$gmailUsername = "from@gmail.com";
$gmailPassword = "mysecretpassword";
$mail_to_send_to = "to@gmail.com";
$your_feedbackmail = "from@gmail.com";

$emailSubject = "Place Subject Here";
$emailContent = "This message can contain <b>HTML</b>";

require '[path_to_your_phpmailer_files]/PHPMailerAutoload.php';

$mail = new PHPMailer;

//$mail->SMTPDebug = 3;                               // Enable verbose debug output

$mail->isSMTP();                                      // Set mailer to use SMTP 
// 0 = off (for production use)
// 1 = client messages
// 2 = client and server messages
$mail->SMTPDebug = 2;                                 //Enable SMTP debugging 
$mail->Debugoutput = 'html';                          //Ask for HTML-friendly debug output
$mail->Host = 'smtp.gmail.com';                       // Specify main and backup SMTP servers
$mail->SMTPAuth = true;                               // Enable SMTP authentication
$mail->Username = $gmailUsername;                 // SMTP username
$mail->Password = $gmailPassword;                           // SMTP password
$mail->SMTPSecure = 'tls';                            // Enable TLS encryption, `ssl` also accepted
$mail->Port = 587;                                    // TCP port to connect to

$mail->setFrom($email_from, $email_from_name);
$mail->addAddress($mail_to_send_to);       
$mail->addReplyTo($your_feedbackmail);

$mail->isHTML(true);                                  // Set email format to HTML

$mail->Subject = $emailSubject;
$mail->Body    = $emailContent; 

if(!$mail->send()) {
    echo 'Message could not be sent.';
    echo 'Mailer Error: ' . $mail->ErrorInfo;
} else {
    echo 'Message was sent, you can send another one';
}

?>