【问题标题】:PHP - EMail sending does not work (no email is received)PHP - 电子邮件发送不起作用(没有收到电子邮件)
【发布时间】:2013-09-20 10:09:39
【问题描述】:

使用以下代码,我应该为我的移动应用程序发送一些电子邮件。但它不起作用。

显示查询已发送!但是没有收到电子邮件....这里出了什么问题?

 <?php
 //setup variables from input    
 $EMAIL = "marco.seiz@bluewin.ch";    

 //setup message    
 $message = "Enquiry from: ";

 $message = wordwrap($message, 70);   


 //email enquiry details to site owner    
 if (mail($EMAIL, "test", $message))    
 {    
  echo "Enquiry sent!";    
 } else    
 {
  echo "fail!";    
 }
?>

php.ini 设置:

[mail function]
; XAMPP: Comment out this if you want to work with an SMTP Server like Mercury
SMTP = smtp.gmail.com
smtp_port = 487

; For Win32 only.
; http://php.net/sendmail-from
sendmail_from = mseiz93@gmail.com

; XAMPP IMPORTANT NOTE (1): If XAMPP is installed in a base directory with spaces (e.g. c:\program files\xampp) fakemail and mailtodisk do not work correctly.
; XAMPP IMPORTANT NOTE (2): In this case please copy the sendmail or mailtodisk folder in your root folder (e.g. C:\sendmail) and use this for sendmail_path.  

; XAMPP: Comment out this if you want to work with fakemail for forwarding to your mailbox (sendmail.exe in the sendmail folder)
sendmail_path = "C:\"\xampp\sendmail\sendmail.exe\" -t"
; XAMPP: Comment out this if you want to work with mailToDisk, It writes all mails in the \xampp\mailoutput folder
;sendmail_path = "C:\xampp\mailtodisk\mailtodisk.exe"

; Force the addition of the specified parameters to be passed as extra parameters
; to the sendmail binary. These parameters will always replace the value of
; the 5th parameter to mail(), even in safe mode.
;mail.force_extra_parameters =

; Add X-PHP-Originating-Script: that will include uid of the script followed by the filename
mail.add_x_header = Off

; Log all mail() calls including the full path of the script, line #, to address and headers
mail.log = "C:\xampp\php\logs\php_mail.log"

提前致谢!

【问题讨论】:

  • 您是否在您的php.ini 文件中设置了任何设置 SMTP 服务器的内容 - 它会接受您的连接吗?
  • 我使用以下选项设置了 php.ini:[邮件功能]; XAMPP:如果您想使用像 Mercury SMTP = smtp.gmail.com smtp_port = 487 这样的 SMTP 服务器,请将此注释掉;仅适用于 Win32。 ; php.net/sendmail-fromsendmail_from = mseiz93@gmail.com
  • 还有 BAM!就是这样,Gmail 将需要 SMTP 身份验证,这是通过 PHP 中的普通 mail() 函数无法实现的。查看 PHPMailer,它会让你进行身份验证(告诉服务器你是谁),然后它会很乐意代表你发送。
  • 我会尝试很多!

标签: php smtp gmail sendmail.exe


【解决方案1】:

需要设置邮件头,调试使用http://mailcatcher.me/小应用程序,它可以捕获所有发送的邮件。 windows也有类似的工具

【讨论】:

    【解决方案2】:

    理想情况下,您应该使用 PHPMailer 或类似工具,以便通过具有身份验证的 SMTP 服务器正确发送电子邮件,但添加这些标头应该会有所帮助。

    话虽如此,Gmail 的 SMTP 服务器肯定需要身份验证,因此尽管您进行了 XAMPP 配置,但邮件可能无法通过。

    <?php
     //setup variables from input    
     $EMAIL = "marco.seiz@bluewin.ch";    
    
     //setup message    
     $message = "Enquiry from: ";
    
     $message = wordwrap($message, 70);   
    
     $headers = "From: mseiz93@gmail.com\n";
     $headers .= "MIME-Version: 1.0\n";
     $headers .= "Content-type: text/plain\n";
    
     //email enquiry details to site owner    
     if (mail($EMAIL, "test", $message, $headers))    
     {    
      echo "Enquiry sent!";    
     } else {
      echo "fail!";    
     }
    ?>
    

    【讨论】:

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