【发布时间】:2015-02-18 10:12:15
【问题描述】:
场景 1:
我正在生成一份报告,以了解更多部门的绩效和参与机构的情况。当我在 GUI 中显示报告时,它可以按部门绩效和参与度(参与的学生人数)排序。
- 对于这种情况,我应该使用原型设计模式吗?
例如:
public abstract class Report implements Cloneable {
private String id;
protected String type;
public void setId(String id){
id=id;
}
public String getId(){
return id;
}
public String getType(){
return type;
}
abstract void getReportData();
public Object clone() {
Object clone = null;
try {
clone = super.clone();
} catch (CloneNotSupportedException e) {
e.printStackTrace();
}
return clone;
}
}
public class PerformanceReport extends Report {
public PerformanceReport(){
type = "Performance";
}
@Override
public void getReportData() {
/* Get report data from database and sort based on performance*/
}
}
public class ParticipationReport extends Report {
public ParticipationReport(){
type = "Participation";
}
@Override
public void getReportData() {
/* Get report data from database and sort based on participation*/
}
}
public class ReportCache {
private static Hashtable<String, Report> reportMap = new Hashtable<String, Report>();
public static Report getReport(String reportid) {
Report cachedReport = reportMap.get(reportid);
return (Report) cachedReport.clone();
}
public static void loadCache() {
ParticipationReport participationReport = new ParticipationReport();
participationReport.setId("1");
reportMap.put(report.getId(),report);
PerformanceReport performanceReport = new PerformanceReport();
performancenReport.setId("2");
reportMap.put(report.getId(),report);
}
}
public class PrototypePatternReport {
public static void main(String[] args) {
ReportCache.loadCache();
Report clonedReport = (Report) ReportCache.getReport("1");
System.out.println("Report : " + clonedReport.getType());
Report clonedReport2 = (Report) ReportCache.getReport("2");
System.out.println("Report : " + clonedReport2.getType());
}
}
- 我的上述概念是否正确?这个概念与原型模式有关吗?
场景 2:
我将测验详细信息(问题和选项、答案)存储在一个对象中,而学生请求测验时,我应该加密答案并给出。对于加密的答案,我应该保留另一个对象。在这种情况下我可以使用原型吗?学生回复后,我应该将学生的答案与现有对象进行比较。
【问题讨论】:
标签: java design-patterns prototype-pattern