在 Python 中使用计数器和列表？

Question

这是我的程序：

msg = input("What is your message? ")

print ()

num_alpha = 26
int_array = [0] * num_alpha

for alpha in range(num_alpha):
    int_array[alpha] = chr(alpha + 65)
    print(int_array[alpha], end = "")

print()

lett = 0
otherch = 0
num_vowels = 0
num_consanants = 0

count_character = [0] * 100000

length = len(msg)

for character in msg.upper():
    if character == "!":
        print("lett =", lett)
        print("other char = ", otherch)
        print("num_vowels = ", num_vowels)
        print("num_consanants = ", num_consanants)
    elif character < "A" or letter > "Z":
        otherch = otherch + 1
        count_character[ord(character)] = count_character[ord(character)] + 1
        print(count_character[ord(character)])
    else:
        lett = lett + 1
        count_character[ord(character)] = count_character[ord(character)] + 1
        print(count_character[ord(character)])

for character in msg:
        print("character", character, "appeared" , count_character[ord(character)] , "times")

我的意思是列出有关消息的各种功能（每个字母出现的次数、元音的数量、非字母字符的数量等），但每次我打印最后一个打印语句时，它都会声明每个角色出现 0 次。 有帮手吗？

编辑：我已经想通了 -

因为之前的循环，而不是：

for character in msg:
    print("character", character, "appeared" , count_character[ord(character)] , "times")

代码需要是：

for character in msg.upper():
    print("character", character, "appeared" , count_character[ord(character)] , "times")

Answer 1

我认为或至少一个问题是，如果您使用 input() 而不是 raw_input()，则需要小心

方法 input() 被认为是未保存的，而 raw_input 真正读入一个字符串/字符

>>> input()
a
Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
   File "<string>", line 1, in <module>
NameError: name 'a' is not defined
>>> raw_input()
a
'a'
>>>

另请注意：

>>> input()
"hello my name is tom"
'hello my name is tom'
>>> raw_input()
"hello my name is tom"
'"hello my name is tom"'
>>>

raw_input() 始终将输入识别为字符串，而您必须输入引号才能让 input() 知道您要输入字符串