Node.js 中的异步循环

Question

async function bald(fileName) {
    try {
        let aPayload = '';
        let aStream = fs.createReadStream(`./tmp/${fileName}`, 'utf8');
        aStream
            .on('data', (chunk) => {
                aPayload += chunk;
            })
            .on('end', async () => {
                let aJson = JSON.parse(aPayload);
                for await (let a of aJson) {
                    console.log(a.id);
                    console.log("Tick");
                    await dbItems.findOne({id: a.id}, (err, result) => {
                        console.log("Something Should Happen!");
                    });
                }
            });
    } catch (e) {
        throw e;
    }
}

这个答案是我想尝试的内容：https://stackoverflow.com/a/50874507/12640130

我发现 forEach 根本不起作用，所以我将其更改为 for ... of，但这对我没有任何影响。有人能找出我的问题吗？

当前输出：

ID
Tick
ID
Tick
ID
Tick
// ... and so on.
Something Should Happen!
Something Should Happen!
Something Should Happen!
// ... and so on.

预期输出：

ID
Tick
Something Should Happen!
ID
Tick
Something Should Happen!
ID
Tick
Something Should Happen!
// ... and so on.

Answer 1

您不能同时使用等待和回调。 它应该是以下之一：

1. 这不会在迭代之前等待结果。

                    dbItems.findOne({id: a.id}, (err, result) => {
                        console.log("Something Should Happen!");
                    });

1. 应该是您正在寻找的。​​li>

                    const result = await dbItems.findOne({id: a.id})
                    console.log("Something Should Happen!");